Question

How much heat will be absorbed by 395g of water when it's temperature is raised by 55°C​

Answer 1

Answer:

$\boxed{\text{91 kJ}}$

Explanation:

The formula for the heat released is

q = mCΔT

Data:

 m = 395 g

 C = 4.184 J·°C⁻¹g⁻¹

ΔT = 55 °C

Calculations:

q = 395 × 4.184 × 55 = 91 000 J = 91 kJ

The water will absorb $\boxed{\textbf{91 kJ}}$ of energy.