First we calculate the number
of moles of Cl2, that is:
moles Cl2 = 1.5*10^10
grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x <span>
So that based on stoichiometry, the number of moles of NaOH =
2x and that of H2 = x mol
mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg
= 1.68 metric tons
<span>mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg
= 0.042 metric tons.</span></span>
Answer:
Option B is correct More hydrogen carbonate is formed
Explanation:
Step 1: Data given
The Principle of Le Chatelier says 'If the concentration of one of the reaction partners changes, the balance will shift to counteract that concentration change.
Step 2: When adding more H2O
For the equation CO2 + H2O --> H2CO3
If the H2O concentration is increased, the system will attempt to undo that change in concentration by shifting the balance to the right, and so the H2CO3 concentration will increase.
Option B is correct More hydrogen carbonate is formed
Answer:
Rn
Explanation:
Rn is the symbol for radon with the atomic number of 86
Answer:
<h2>1.806 × 10²³ atoms</h2>
Explanation:
The number of sodium atoms can be found by using the formula
<h3>N = n × L</h3>
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
N = 0.3 × 6.02 × 10²³
We have the final answer as
<h3>1.806 × 10²³ atoms</h3>
Hope this helps you
Answer:
238 amu
Explanation:
(234 * 0.0001) + (235 * 0.0071) + (238 * 0.9928) = 238
