If the rod is in rotational equilibrium, then the net torques acting on it is zero:
∑ τ = 0
Let's give the system a counterclockwise orientation, so that forces that would cause the rod to rotate counterclockwise act in the positive direction. Compute the magnitudes of each torque:
• at the left end,
τ = + (50 N) (2.0 m) = 100 N•m
• at the right end,
τ = - (200 N) (5.0 m) = - 1000 N•m
• at a point a distance d to the right of the pivot point,
τ = + (300 N) d
Then
∑ τ = 100 N•m - 1000 N•m + (300 N) d = 0
⇒ (300 N) d = 1100 N•m
⇒ d ≈ 3.7 m
Answer:
B) 18.5 m/
s west
Explanation:
Scalar quantity has MAGNITUDE only
Vector quantity has MAGNITUDE and DIRECTION
Hope this is correct and helpful
HAVE A GOOD DAY!
Answer:
8.3
Explanation:
thats what i think sorry if its wrong im ok at doing this stuff
A wooden log is displaced to a distance of 20m in 10 seconds by applying 500N effort . Calculate the workdone and power...
Solution,
displacement = 20 m
time = 10 sec
force = 500 N
work done = ?
power = ?
Now ,
work done = f × s
= 500 N × 20 m
= 10000 j
Now ,
~nightmare 5474~
