1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
QveST [7]
3 years ago
8

I’m ugly ain’t I ??????

Physics
2 answers:
olga55 [171]3 years ago
7 0
Aw don’t say that! I’m sure your beautiful:)
igor_vitrenko [27]3 years ago
3 0

Answer:

No. God is beautiful right? He created everyone in His own image so you are not ugly.

You might be interested in
3. How is using a model to study cells helpful?
4vir4ik [10]

Answer:

Yes, it is very helpful.

Explanation:

It's helpful since in a cell, plant or animal, there are a lot of different things. It's hard to memorize everything and know what they look like. Using a model can help you memorize everything better and even understand it better. If someone asked me where or what something was in a cell I think I would be able to recognize it better.

I hope this helps!

6 0
3 years ago
When a certain isotope, such as U-238, is hit by a neutron, it will always split into the same smaller nuclei.
nadezda [96]

Answer: falss

Explanation:

4 0
3 years ago
Read 2 more answers
MRU(movimiento rectilineo uniforme) un movil viaja en linea recta con una velocidad media de 12metros /segundos durante 9segundo
liubo4ka [24]

Answer:

a) 141.6m

b) 8.4m/s

Explanation:

a) to find the total displacement you use the following formula for each trajectory. Next you sum the results:

x_1=v_1t_1=(12m/s)(9s)=108m\\\\x_2=v_2t_2=(4.8m/s)(7s)=33.6m\\\\x_T=x_1+x_2=108m+33.6m=141.6m

hence, the total distance is 141.6m

b) the mean velocity of the total trajectory is given by:

v_m=\frac{v_1+v_2}{2}=\frac{12m/s+4.8m/s}{2}=8.4\frac{m}{s}

hence, the mean velocity is 8.4 m/s

8 0
3 years ago
Expansionary monetary policies would likely cause
Jlenok [28]

Answer:

TRUE

Explanation:i've seen one and please make me the brainlest

6 0
1 year ago
A 110 kg hoop rolls along a horizontal floor so that the hoop's center of mass has a speed of 0.220 m/s. How much work must be d
Softa [21]

Answer:

the work that must be done to stop the hoop is 2.662 J

Explanation:

Given;

mass of the hoop, m = 110 kg

speed of the center mass, v = 0.22 m/s

The work that must be done to stop the hoop is equal to the change in the kinetic energy of the hoop;

W = ΔK.E

W = ¹/₂mv²

W = ¹/₂ x 110 x 0.22²

W = 2.662 J

Therefore, the work that must be done to stop the hoop is 2.662 J

6 0
3 years ago
Other questions:
  • An object starts at rest then accelerates at a rate of 5m/s^2 for 1 second and then 2m/s^2 for 2 seconds. What is the average ac
    10·1 answer
  • Give an example of a situation in which you would describe an object's position in
    9·1 answer
  • Properties of macroscopic systems! Tummarize your present understanding of the properties of macroscopic systems.
    11·1 answer
  • A block of a plastic material floats in water with 35.6% of its volume under water. What is the density of the block in kg/m3
    9·1 answer
  • A constant torque of 26.6 N · m is applied to a grindstone for which the moment of inertia is 0.162 kg · m2 . Find the angular s
    14·2 answers
  • The element chlorine has two naturally occurring isotopes. About 75% of chlorine isotopes are Cl35 and about 25% are Cl37. What
    10·1 answer
  • A pesticide kills insects by disabling the ribosomes in their cells.
    9·2 answers
  • The height of the tide measured at a seaside community varies according to the number of hours t after midnight. If the height h
    10·1 answer
  • If a force of 1.0 N pulled up and parallel to the surface of the incline is required to raise the mass back to the top of the in
    14·1 answer
  • a 9.0-kg dog runs at 4.0 m/s and jumps onto a stationary skateboard the mas of the skateboard is 1.0 m/s what speed is the speed
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!