Answer:
1.25 atm.
Explanation:
Step 1:
Data obtained from the question. This includes the following:
Initial volume (V1) = 20L
Initial temperature (T1) = 25°C
Initial pressure = 1 atm
Final temperature (T2) = 100°C
Final volume (V2) = constant i.e remain the same
Final pressure (P2) =?
Step 2:
Conversion of celsius temperature to Kelvin temperature. This is illustrated below:
Temperature (Kelvin) = temperature (celsius) + 273
Initial temperature (T1) = 25°C = 25°C + 273 = 298K
Final temperature (T2) = 100°C = 100°C + 273 = 373K
Step 3:
Determination of the final pressure of the gas. This is illustrated below:
Since the volume is constant, the following equation, P1/T1 = P2/T2 will be used to obtain the final pressure of gas as follow:
P1/T1 = P2/T2
Initial temperature (T1) = 298k
Initial pressure = 1 atm
Final temperature (T2) = 373K
Final pressure (P2) =?
P1/T1 = P2/T2
1/298 = P2 /373
Cross multiply to express in linear form
298 x P2 = 1 x 373
Divide both side by 298
P2 = 373/298
P2 = 1.25 atm.
Therefore, the pressure of the heated gas is 1.25 atm.
