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Zinaida [17]
3 years ago
7

3. Once magnesium (Mg) gives up electron(s) to become an ion, it will become

Chemistry
1 answer:
xeze [42]3 years ago
5 0

Answer:

Option B. Cation that is smaller than the original atom.

Explanation:

Magnesium is a divalent element. This implies that magnesium can give up 2 electrons to become an ion (cation) as shown below:

Mg —> Mg²⁺ + 2e¯

Next, we shall write the electronic configuration of magnesium atom (Mg) and magnesium ion (Mg²⁺). This can be written as follow:

Mg (12) = 2, 8, 2

Mg²⁺ (10) = 2, 8

From the above illustration, we can see that the magnesium atom (Mg) has 3 shells while the magnesium ion (Mg²⁺) has 2 shells.

This simply means that the magnesium ion (Mg²⁺) i.e cation is smaller that the original magnesium atom (Mg).

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A uniform cylinder of mass 4.3 kg and radius 0.4 m rolls down a ramp inclined at an angle 0.15 radians to the horizontal. what i
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The cylinder's acceleration is

a=\frac{gsin}{1+\frac{I}{mrL} }

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<h3>How do you determine a cylinder's acceleration?</h3>

The cylinder's complete radius, R, from the center marks the contact point, therefore the torque created by friction is given by fR = I\alpha, where is the rotating acceleration. This rotational acceleration's corresponding linear acceleration, \alpha, is equal to R. The cylinder, which has its mass concentrated in its center, triumphs in the competition, followed by the disc and the hoop, with their respective final velocities being roughly 1.4:1.2:1. We can also see that our findings are unaffected by the cylinders' masses.

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2 years ago
What is the name of bird W?
Bingel [31]

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2 years ago
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7 0
3 years ago
An unknown amount of mercury (II) oxide was decomposed in the lab. Mercury metal was formed and 5.20 L of oxygen was released at
Yakvenalex [24]

Answer:

  • <u>68.3g</u>

Explanation:

<u>1. Word equation:</u>

  • <em>mercury(II) oxide → mercury + oxygen </em>

<u>2. Balanced molecular equation:</u>

  • 2HgO → 2Hg + O₂(g)

<u>3. Mole ratio</u>

Write the ratio of the coefficients of the substances that are object of the problem:

       2molHgO/1molO_2

<u>4. Calculate the number of moles of O₂(g)</u>

Use the equation for ideal gases:

          pV=nRT\\\\\\n=\dfrac{pV}{RT}\\\\\\n=\dfrac{0.970atm\times5.20L}{0.08206atm.L/K.mol\times 390.0K}\\\\\\n=0.1576mol

<u>5. Calculate the number of moles of HgO</u>

         \dfrac{2molHgO}{1molO_2}\times 0.1576molO_2=0.315molHgO

<u>6. Convert to mass</u>

  • mass = # moles × molar mass

  • molar mass of HgO: 216.591g/mol

  • mass = 0.315mol × 216.591g/mol = 68.3g

7 0
3 years ago
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