3 N
10-7= 3
the arrows are opposing each other.
According to Dalton's Law of Partial pressure, the pressure exerted by a mixture of non-reacting gases is equal to the sum of their partial pressure.
Mathematically,
Total Pressure = P₍₁₎ + P₍₂₎ + P₍₃₎ + ....... ------(1)
Data given:
Partial pressure of Nitrogen = P₍₁₎ = 587 mmHg
Partial pressure of Oxygen = P₍₂₎ = 158 mmHg
Partial pressure of Argon = P₍₃₎ = 7.00 mmHg
Putting these values in eq 1.
Total Pressure = 587 mmHg + 158 mmHg + 7 mmHg
Total Pressure = 752 mmHg
Answer:
63.58 g O
Explanation:
To calculate the mass of O atoms, the number of moles of O atoms are needed and can be calculated as follows:
n (no. of moles) = nA ÷ 6.02 × 10^23
n = 2.393 x 10^24 ÷ 6.02 × 10^23
n = 0.398 × 10^ (24-23)
n = 0.398 × 10^1
n = 3.98moles.
To calculate the mass of Oxygen, we use the following formula:
moles = mass/molar mass
Molar mass of O = 16.
3.98 = m/16
m = 3.98 × 16
m = 63.68grams of Oxygen.
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