Answer:
2940.1 joules would you burn in climbing stairs all day.
Explanation:
Work = W = F
d
going up stairs would be against force of gravity
W = mgh
where h is the height
the question is not complete because we need speed or distance
h = v
t
so assuming 1 step per second
h = 86,400 steps
7inchs/step
0.0254 m/inch
h = 15362 m
so from this
W = 800 N
15362
= 12289600 J
that means YOU need 12289600 J to walk 1 step per second all day
divide that by 4180 J /Kcal
Kcal = 
= 
= 2940.1 Kcal
if you ran faster you would use more energy 2 steps per second would mean 5880 Kcal.
Answer:
300000 J / 400 J/s = 750 s = 12.5 minutes
Explanation:
Answer:
alpha=53.56rad/s
a=5784rad/s^2
Explanation:
First of all, we have to compute the time in which point D has a velocity of v=23ft/s (v0=0ft/s)

Now, we can calculate the angular acceleration (w0=0rad/s)


with this value we can compute the angular velocity

and the tangential velocity of point B, and then the acceleration of point B:

hope this helps!!
Answer:
(a) The angle of projection is 63 degree.
(b) The velocity of projection is 24.5 m/s.
Explanation:
Height, h = 1 m
horizontal distance, d = 50 m
time, t = 4.5 s
Let the initial velocity is u and the angle is A.
(a) Horizontal distance = horizontal velocity x time
50 = u cos A x 4.5
u cos A = 11.1 .....(1)
Use second equation of motion in vertical direction

Divide (2) by (1)
tan A = 1.97
A = 63 degree
(b) Substitute the value of A in equation (2)
u x sin 63 = 21.8
u = 24.5 m/s
Answer:
a) 
b) 
c) 
Explanation:
Given:
- voltage of the battery,

- energy storage capacity of the battery,

- speed of the car,

a)
power drawn by the car, 
<u>Now the Current delivered to the motor:</u>
we the relation between the power and electrical current,



b)
<u>Distance travelled before battery is out of juice:</u>
we first find the time before the battery runs out,



Now the distance:



c)
When the head light of 55 W power is kept on while moving then the power consumption of the car is:



<u>Now the time of operation of the car:</u>



<u>Now the distance travelled:</u>


