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Verdich [7]
3 years ago
15

Please LIKE & SHARE to keep our generators available!

Engineering
2 answers:
bekas [8.4K]3 years ago
6 0
Hi i’m confused is this supposed to be a question
ehidna [41]3 years ago
5 0

Answer:

Is this a questions

Explanation:

please I don't understand

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4.
Roman55 [17]

Answer:

D

Explanation:

6 0
3 years ago
Read 2 more answers
Air, at a free-stream temperature of 27.0°C and a pressure of 1.00 atm, flows over the top surface of a flat plate in parallel f
Morgarella [4.7K]

Answer:

Explanation:

Given that:

V = 12.5m/s

L= 2.70m

b= 0.65m

T_{ \infty} = 27^0C= 273+27 = 300K

T_s= 127^0C = (127+273)= 400K

P = 1atm

Film temperature

T_f = \frac{T_s + T_{\infty}}{2} \\\\=\frac{400+300}{2} \\\\=350K

dynamic viscosity =

\mu =20.9096\times 10^{-6} m^2/sec

density = 0.9946kg/m³

Pr = 0.708564

K= 229.7984 * 10⁻³w/mk

Reynolds number,

Re = \frac{SUD}{\mu} =\frac{\ SUl}{\mu}

=\frac{0.9946 \times 12.5\times 2.7}{20.9096\times 10^-^6} \\\\Re=1605375.043

we have,

Nu=\frac{hL}{k} =0.037Re^{4/5}Pr^{1/3}\\\\\frac{h\times2.7}{29.79\times 10^-63} =0.037(1605375.043)^{4/5}(0.7085)^{1/3}\\\\h=33.53w/m^2k

we have,

heat transfer rate from top plate

\theta _1 =hA(T_s-T_{\infty})\\\\A=Lb\\\\=2.7*0.655\\\\ \theta_1=33.53*2.7*0.65(127/27)\\\\ \theta_1=5884.51w

7 0
3 years ago
Cell phones require powerful batteries in orde to work effectively. Which activity is best described as an engineering endeavor
natta225 [31]
Where are the options?
8 0
3 years ago
Diffusion of Ammonia in an Aqueous Solution Ammonia (A)-water (B) solution ta 278 K and 4 mm thick is in contact with an organic
Tom [10]

Answer:

Explanation:

The pictures below shows the whole explanation for the problem

4 0
4 years ago
You are an engineer in an electric-generation station. You know that the flames in the boiler reach a temperature of 1200 K and
olga nikolaevna [1]

Answer:

<em>The maximum efficiency the plant will ever achieve is 75%</em>

<em>Explanation:</em>

From the question given, we recall the following:

<em>Th flames in the boiler reaches a temperature of = 1200K</em>

<em>the cooling water is = 300K</em>

<em>The maximum efficiency the plant will achieve is defined as:</em>

Let nmax = 1 - Tmin /Tmax

Where,

Tmin = Minimum Temperature in plants

Tmax = Maximum Temperature in plants

The temperature of the cooling water  = Tmin = 300K

The temperature of the flames in boiler = Tmax = 1200k=K

The maximum efficiency becomes:

nmax =  1 - Tmin /Tmax

nmax =  1 - 300 /1200

nmax =  1-1/4 =0.75

nmax =  75%

5 0
4 years ago
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