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djverab [1.8K]
2 years ago
7

In the lab you react 20g of potassium iodide with an excess of lead (II) nitrate to form 15g of lead (II) iodide precipitate. Wh

at is the percent yield of your experiment?
What is the balanced equation for this question?
What is the first ratio used to solve this question?
What is the second ratio used to solve this question?
What is the third ratio used to solve this question?
What is the percentage yield?
Chemistry
1 answer:
sveticcg [70]2 years ago
8 0

Answer:

C                  

Explanation:

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In a titration experiment, 31.4 mL of 1.120 M HCOOH is neutralized by 16.3 mL of Ba(OH)2. What is the concentration of the Ba(OH
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Answer : The concentration of the Ba(OH)_2 solution is, 2.16 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCOOH

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ba(OH)_2.

We are given:

n_1=1\\M_1=1.120M\\V_1=31.4mL\\n_2=2\\M_2=?\\V_2=16.3mL

Putting values in above equation, we get:

1\times 1.120M\times 31.4mL=2\times M_2\times 16.3mL\\\\M_2=2.16M

Thus, the concentration of the Ba(OH)_2 solution is, 2.16 M

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