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Vsevolod [243]
3 years ago
12

¿Cual es porcentaje de una solucion que contiene 10g de sal disueltos en 500 mL de solución?

Chemistry
1 answer:
never [62]3 years ago
4 0

Answer:

0.02 g/ml

Explanation:

si dividimos 10 con 500, es decir, 10/500, obtenemos 0.02. Las unidades serán g / ml.

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Is nickel cyanide a ionic or covalent bond
dlinn [17]

Answer:

Ionic

Explanation:

Because there's a metal and nonmetal present in this bond, it is ionic. Covalent bonds occur when there are only metals present. Hope this helps.

3 0
3 years ago
Four students all do the same experiment for the science fair. They test reaction times for pushing a button when a specific col
emmasim [6.3K]
Sorry, Cant really tell how to differentiate the students and trial times
3 0
3 years ago
Protons Ha and Hb in the compound given are _________. homotopic enantiotopic diastereotopic mesotopic none of these
jek_recluse [69]

Protons Ha and Hb in the compound given are enantiotopic.

<h3>What are enantiotopic protons?</h3>

Enantiotopic protons can be defined as those protons that can be replaced by another groups like deuterium.

<h3>What is a compound?</h3>

A compound is a substance which contains two or more elements chemically combined together.

So therefore, Protons Ha and Hb in the compound given are enantiotopic.

Learn more about enantiotopic protons:

brainly.com/question/24106290

#SPJ1

8 0
2 years ago
Ephedrine, a central nervous system stimulant, is used in nasalsprays as a decongestant. this compound is a weak organic base: {
sashaice [31]

Ephedrine, a central nervous system stimulant, is used in nasal sprays as a decongestant. This compound is a weak organic base:

C10H15ON (aq) + H2O (l) -> C10H15ONH+ (aq) + OH- (aq)

A 0.035 M solution of ephedrine has a pH of 11.33.

a) What are the equilibrium concentrations of C10H15ON, C10H15ONH<span>+, and OH-</span>?

b) Calculate <span>Kb</span> for ephedrine.

c(C₁₀H₁₅NO) = 0,035 M.<span>
pH = 11,33.
pOH = 14 - 11,33 = 2,67.
[OH</span>⁻] = 10∧(-2,67) = 0,00213 M.<span>
[OH</span>⁻] = [C₁₀H₁₅NOH⁺] = 0,00213 M.<span>
[</span>C₁₀H₁₅NO] = 0,035 M - 0,00213 M = 0,03287 M.<span>
Kb = [OH</span>⁻] · [C₁₀H₁₅NOH⁺] / [C₁₀H₁₅NO].<span>
Kb = (</span>0,00213 M)² / 0,03287 M = 1,38·10⁻⁴.

3 0
3 years ago
A concentration cell consists of two Sn/Sn2+ half-cells. The solution in one half-cell A is 0.13 M Sn(NO3)2 and is 0.87 M Sn(NO3
alina1380 [7]
Base on your question where a concentration cell consist of two SN/SN2+half cells. The solution in one half cell A is 0.13M SN(NO3)2 and is 0.87 M Sn(NO3)2 in the other half cell to get the cell potential at 25 degree the answer is 0.059/2 log0.13/0.87
6 0
3 years ago
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