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Vsevolod [243]
3 years ago
12

¿Cual es porcentaje de una solucion que contiene 10g de sal disueltos en 500 mL de solución?

Chemistry
1 answer:
never [62]3 years ago
4 0

Answer:

0.02 g/ml

Explanation:

si dividimos 10 con 500, es decir, 10/500, obtenemos 0.02. Las unidades serán g / ml.

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Which of the following examples is a molecule with a covalent bond?
serious [3.7K]

Answer:

B. CO

Explanation:

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3 years ago
Compare the values of the spin quantum number for two electrons in the same orbital
Leokris [45]
If there are 2 electrons in the same orbital, the spin numbers would be different for both of these 2 electrons. One would have an up spin and the other a down spin.
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3 years ago
What is the relationship between melting/boiling point and intermolecular forces
sattari [20]
Boiling points are a measure of intermolecular forces. The intermolecular forces increase with increasing polarization of bonds. Boiling point increases with molecular weight, and with surface area.
8 0
2 years ago
Qué tipo de reacción es el siguiente? CH4 + 02<br><br> CO2 + H2O
Tatiana [17]

Answer:

Combustion reaction

Explanation:

Let's consider the following balanced equation.

CH₄ + 2 O₂  ⇒ CO₂ + 2 H₂O

This reaction is known as a combustion reaction, in which a compound reacts with oxygen to form a compound of carbon and water.

  • If the product is carbon dioxide, the combustion is complete.
  • If the product is carbon monoxide or carbon, the combustion is incomplete.
7 0
3 years ago
Read 2 more answers
How many particles are in 47.7 g of Magnesium? (Round the average
Lynna [10]

Answer:

1.18 × 10²⁴ particles Mg

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

47.7 g Mg

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of Mg - 24.31 g/mol

<u>Step 3: Convert</u>

<u />47.7 \ g \ Mg(\frac{1 \ mol \ Mg}{24.31 \ g \ Mg} )(\frac{6.022 \cdot 10^{23} \ particles \ Mg}{1 \ mol \ Mg} ) = 1.18161 × 10²⁴ particles Mg

<u>Step 4: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1.18161 × 10²⁴ particles Mg ≈ 1.18 × 10²⁴ particles Mg

3 0
2 years ago
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