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Lyrx [107]
2 years ago
10

A spring has a spring constant of 330 n/m. how far is the spring compressed when 150 newtons of force are used?

Physics
1 answer:
vitfil [10]2 years ago
7 0

Answer:

b. 0.45 meters

Explanation:

Given the following data;

Spring constant, k = 330 N/m

Force = 150 N

To find the extension of the spring;

Mathematically, the force exerted on a spring is given by the formula;

Force = spring constant * extension

Substituting into the formula, we have;

150 = 330 * extension

Extension, e = 150/330

Extension, e = 0.45 meters

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AleksandrR [38]
After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward. 
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is g=9.81 m/s^2 at every point of the motion, and therefore also when the baseball is at its highest point.
5 0
2 years ago
The world energy consumption was about 6*10^22 J. How much area must a parallel plate capacitor need to store this energy Assume
Nastasia [14]

Answer:

A = 5 \times 10^{32} m^2

Explanation:

As we know that the energy stored in the capacitor is given as

Q = \frac{1}{2}CV^2

here we know that

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also we know that

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now we have

6 \times 10^{22} = \frac{1}{2}C(5^2)

C = 4.8 \times 10^{21} F

now we know the formula of capacitance

C = \frac{\epsilon_0 A}{d}

4.8 \times 10^{21} = \frac{(8.85 \times 10^{-12})(A)}{1}

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3 0
3 years ago
An electric circuit through which no current flows is known as?
Afina-wow [57]
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4 0
3 years ago
Read 2 more answers
A 6 kilogram block in outer space is moving at -100 m/s (to the left). It suddenly experiences three forces as shown below (in t
Blizzard [7]

Answer:

x = 1474.9 [m]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces must be equal to the product of mass by acceleration.

We must understand that when forces are applied on the body, they tend to slow the body down to stop it.

So as the body continues to move to the left, it is slowing down. Therefore we must calculate this deceleration value using Newton's second law. We must perform a sum of forces on the x-axis equal to the product of mass by acceleration. With leftward movement as negative and rightward forces as positive.

ΣF = m*a

10 +12*sin(60)= - 6*a\\a = - 3.39[m/s^{2}]

Now using the following equation of kinematics, we can calculate the distance of the block, before stopping completely. The initial speed must be 100 [m/s].

v_{f}^{2} =v_{o}^{2}-2*a*x

where:

Vf = final velocity = 0 (the block stops)

Vo = initial velocity = 100 [m/s]

a = - 3.39 [m/s²]

x = displacement [m]

0 = 100^{2}-2*3.39*x\\x=\frac{10000}{2*3.39}\\x=1474.9[m]

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2 years ago
What is the acceleration of a 1107 kg car as it comes to rest with a force of 2242 N in 6.9 seconds?
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acceleration is 2.025m/s².

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