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3 years ago

3. Jasmine pousse un objet sur une distance de

1 answer:

5 0

Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?

Answer:

30J

Explanation:

Given parameters:

Distance moved = 15m

Work done = 450J

Unknown:

Strength Jasmine applied = ?

Solution:

The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.

Now;

Work done = Force x distance

So;

450 = Force x 15

Force = $\frac{450}{15}$ = 30J

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Question 4

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Answer:

H(aq) + NO3 (aq) + HF(aq)

Explanation:

In the given mixture of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water the major species present are H(aq) + NO3 (aq) + HF(aq).

On the reaction of HNO3 (Nitric Acid) and HF (hydrofluoric acid) in water , it will give a polar solution and will form a homogenous mixture.

Hence, the correct answer is "H(aq) + NO3 (aq) + HF(aq)".

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3 years ago

Consider two equal-volume balloons under the same conditions of temperature and pressure. One contains helium, and the other con

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Answer:

1. Number of gas particles (atoms or molecules)

2. Number of moles of gas

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Explanation:

Since the two gas has the same volume and are under the same conditions of temperature and pressure,

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1. They have the same number of mole because 1 mole of any gas at stp occupies 22.4L. Now both gas will occupy the same volume because they have the same number of mole

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3. Being under the same conditions of temperature and pressure, they both have the same average kinetic energy. The kinetic energy of gas is directly proportional to the temperature. Now that both gas are under same temperature, their average kinetic energy are the same.

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3 years ago

Consider X + Z -> ?

Licemer1 [7]

Answer:

Explanation:

Element Z acquires two electrons from element X for stability

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3 years ago

A certain chemical reaction releases 31.0 kj/g of heat for each gram of reactant consumed. How can you calculate what mass of re

Aleksandr-060686 [28]

Answer:

See explanation.

Explanation:

Hello!

In this case, since we know the heat of reaction per gram of reactant and we should know the total energy of reaction, but it is not there, we are going to assume it is 1200 J as usual in these problems, so you can change it to whatever your given heat is.

In such a way, we set up the math as shown below:

$m= 1200J*\frac{1kJ}{1000J}*\frac{1g}{31.0kJ}$