3. Jasmine pousse un objet sur une distance de
1 answer:
Jasmine pushes an object a distance of 15 m at constant speed. It produces a 450J of work on the object. What strength Jasmine does it exert on the object?
Answer:
30J
Explanation:
Given parameters:
Distance moved = 15m
Work done = 450J
Unknown:
Strength Jasmine applied = ?
Solution:
The strength Jasmine applied or exerted on the object is the force of pull that cause the motion of the object and the distance it was moved.
Now;
Work done = Force x distance
So;
450 = Force x 15
Force = = 30J
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Answer:
2.8g/cm³
Explanation:
Given parameters:
Mass of cube = 42g
Volume of cube = 15cm³
Unknown:
Density of the cube = ?
Solution:
Density is defined as the mass per unit volume of a substance. It is mathematically expressed as:
Density =
So;
Density = = 2.8g/cm³
Answer:
The sample of nitrogen must be taken to 267 .
Explanation:
Let's assume nitrogen gas behaves ideally.
Here amount of nitrogen gas in both states remain constant.
So, in accordance with combined gas law for a given amount of an ideal gas in two different states:
where and
are initial and final pressure respectively.
and
are initial and final volume respectively.
and
are initial and final temperature (in kelvin scale) respectively.
Here ,
,
and
So
540 K = (540-273) = 267
So the sample of nitrogen must be taken to 267 .