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madreJ [45]
2 years ago
6

Two foam peanuts become equally charged as they fall out of a cardboard box. Each foam peanut carries a charge of 8 x 10^-4 C. I

f the peanuts are 0.05 m apart, what is the electric force between them? Assume that k = 9 x 10^9 Nm^2/C^2. Use Coulomb’s law equation: F = kq1q2/r^2.
A. 115,200 N
B. 2,304,000 N
C. 0.000000434 N
D. 0.0000086 N
Physics
1 answer:
jok3333 [9.3K]2 years ago
7 0

Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

F_e=9\,\,10^9\,  \,  \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\,  \,  \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N

which agrees with answer B provided.

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2 years ago
(a) A light-rail commuter train accelerates at a rate of 1.35 m/s2 . How long does it take to reach its top speed of 80.0 km/h,
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Answer:

(a) Time t = 16.46 sec

(b) Time t =13.466 sec

(c) Deceleration = 2.677m/sec^2

Explanation:

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Acceleration a=1.35m/sec^2

Final speed v = 80 km/hr

80km/hr=\frac{80\times 1000}{3600sec}=22.22m/sec

From first equation of motion v =u+at

So t=\frac{v-u}{a}=\frac{22.22-0}{1.35}=16.46 sec

(b) Now initial speed u = 22.22 m/sec

As finally train comes to rest so final speed v=0 m/sec

Deceleration a=1.65m/sec^2

So t=\frac{v-u}{a}=\frac{0-22.22}{-1.65}=13.466 sec

(c) We have given that initial velocity = 80 km/hr = 22.22 m/sec

Final velocity v = 0 m/sec

Time t = 8.30 sec

So acceleration is given by

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3 years ago
Every football field has two 300kg field goal posts separated by 110m of football field (that includes the endzones). What is th
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Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²

Gravitational force (F) =?

The gravitational force between the two goal posts can be obtained as follow:

F = GM1M2 / r²

F = 6.67×10¯¹¹ × 300 × 300 / 110²

F = 6.003×10¯⁶ / 12100

F = 4.96×10¯¹⁰ N

Therefore the gravitational force between the two goal posts is 4.96×10¯¹⁰ N

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