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madreJ [45]
3 years ago
6

Two foam peanuts become equally charged as they fall out of a cardboard box. Each foam peanut carries a charge of 8 x 10^-4 C. I

f the peanuts are 0.05 m apart, what is the electric force between them? Assume that k = 9 x 10^9 Nm^2/C^2. Use Coulomb’s law equation: F = kq1q2/r^2.
A. 115,200 N
B. 2,304,000 N
C. 0.000000434 N
D. 0.0000086 N
Physics
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

Answer labeled B : 2,304,000 N

Explanation:

Recall the formula for the electric force:

F_e=9\,\,10^9\,  \,  \frac{q_1*q_2}{d^2} \\F_e=9\,\,10^9\,  \,  \frac{8\,10^{-4}*8\,10^{-4}}{0.05^2} \\F_e=2,304,000\,\,N

which agrees with answer B provided.

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If y(t)y(t) describes the position with time, what is the proper formula for velocity with time? (Recall velocity is related to
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Answer:

Although this question is not complete, I would give a general solution to this kind of problems.

If y(t) describes the position of a body with time such that

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Then

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Explanation:

As an example supplies the position of a particle is given by

y(t) = 4t³- 3t² + 9

V(t) = 4x3t²- 3x2t¹

V(t) = d(t)/dt = 12t² - 6t.

Another example,

If y(t) = 15t³ - 2t² + 30t -80

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Basically, in the equations above the powers of t reduces by one when computing the velocity function from y(t) by differentiation (calculating the derivative of y(t)). The constant term C (9 and 80 in the functions of y(t) in examples 1and 2 above) reduces to zero because the derivative of a constant (and ordinary number without the t attached to it) is always zero.

One last example,

y(t) = 2t^6 -3t²

V(t) = d(t)/dt = 12t^5 - 6t

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