Answer:
2.0 s, 200 m
Explanation:
Time to hit the ground depends only on height. Since the plane is at the same height, the weight lands at the same time as before, 2.0 s.
Since the plane is going twice as fast, the weight will travel twice as far (ignoring air resistance). So it will travel a horizontal distance of 200 m.
Answer:
1- The lank with the least slope will be the easiest to climb because it will require the least force.
2- All three paths will require the same energy as the work done will be the same in all three cases.
Explanation:
1- Work done W = Force x Displacement i.e. W = F × cosФ where 'Ф' is the angle between force and displacement. Smaller the angle least is the force required to climb. Hence the path with least slope will be easier to climb.
2- Since W = F × cosФ as the angle increase cos Ф decrease which means the slope is increase and consequently the force required also increases but the total work done remains the same. Hence the energy required to climb all three Lanks will be the same.
A = (Vf-Vi) / t,
a = (6-0)/3 = 2m/s^2,
F = ma = 2 * 2 = 4N
Answer:
a) I = 10⁻² W / m², b) β = 104.8 db
Explanation:
a) For this exercise we use the definition of decibels
β = 10 log ![\frac{I}{I_o}](https://tex.z-dn.net/?f=%5Cfrac%7BI%7D%7BI_o%7D)
where I and Io are the intensities produced and the sound threshold
I₀ = 10⁻¹² W / m²
log \frac{I}{I_o} = β / 10
I = Io ![10^{\beta /10}](https://tex.z-dn.net/?f=10%5E%7B%5Cbeta%20%2F10%7D)
let's calculate
I = 10⁻¹² ![10^{100/10}](https://tex.z-dn.net/?f=10%5E%7B100%2F10%7D)
I = 10⁻² W / m²
b) each toad produces the same sound for which the total intensity is
I_total = 3 I
I_total = 3 10⁻² W / m²
expressed in decibels
β = 10 log (
)
β = 104.8 db