If the resistance of each bulb is 3 ohms, and they are connected across the battery, then current will flow through them.
In series, the two 3-ohm bulbs will look like a single 6-ohm resistance.
Current = (voltage) / (resistance) = (12v) / (6 ohms) = 2 Amperes.
The battery will need to deliver some power to the circuit.
Power = (voltage) x (current) = (12v) x (2 Amperes) = 24 watts .
Each bulb will dissipate 12 watts, in the form of light and heat.
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40m/s2 because its already traveling 4m/s soo in 10 second it will be at 40 miles per seconds
4*10
=40
Answer:
6.0 s
98 m/s
Explanation:
The radius of the planet is much bigger than the height of the tower, so we will assume the acceleration is constant. Neglect air resistance.
Acceleration due to gravity on this planet is:
a = GM / r²
a = (6.67×10⁻¹¹ m³/kg/s²) (2.7 × 1.48×10²³ kg) / (1.7 × 750,000 m)²
a = 16.4 m/s²
The height of the tower is:
Δy = 96 × 3.05 m
Δy = 293 m
Given v₀ = 0 m/s, find t and v.
Δy = v₀ t + ½ at²
(293 m) = (0 m/s) t + ½ (16.4 m/s²) t²
t = 6.0 s
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (16.4 m/s²) (293 m)
v = 98 m/s
