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Ivahew [28]
3 years ago
12

ingrid kicks a football with an initial velocity of 12 m/s at an angle 45 relative to the ground. what is the horizontal compone

nt of the initial velocity to the nearest tenth
Physics
2 answers:
snow_lady [41]3 years ago
8 0

is correct answer => 8.5 m/s


nydimaria [60]3 years ago
4 0

Let's assume that the coordinate system is defined as positive in the first quadrant.

The system has its origin in the place where Ingrid kicks the football ball.

We have then that the horizontal component is given by:

x = 12cos (45)

Rewriting we have:

x = 12 ( \frac{\sqrt{2}}{2})\\x = 8.485281374

Rounding the obtained result we have:

x = 8.5 \frac{m}{s}

Answer:

The horizontal component of the initial velocity to the nearest tenth is:

x = 8.5 \frac{m}{s}

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Explanation:

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the magnitude of the second vector(say) \left |  b\right |=7\ km

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\left |  \vec{R}\right |=\sqrt{a^2+b^2+2ab\cos \theta}

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3 years ago
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Keith_Richards [23]

Answer:

Explanation:

  a )

from lens makers formula

\frac{1}{f} =(\mu-1)(\frac{1}{r_1} -\frac{1}{r_2})

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putting the values

\frac{1}{1.8} =(1.38-1)(\frac{1}{.5} -\frac{1}{r_2})

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r₂ = 1.86 cm .

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b )

object distance u = 25 cm

focal length of convex lens  f  = 1.8 cm

image distance  v   = ?

lens formula

\frac{1}{v} - \frac{1}{u} = \frac{1}{f}

\frac{1}{v} - \frac{1}{-25} = \frac{1}{1.8}

\frac{1}{v} = \frac{1}{1.8} -\frac{1}{25}

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c )

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= .0776 x 10 mm

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ira [324]

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Agata [3.3K]

Answer:

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