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Line up in a direction parallel to the magnetic field lines<span />
Answer:
Explanation:
Given
average speed of train
Maximum acceleration=0.05g
Now centripetal acceleration is


r=7346.93 m
(b)Radius of curvature=900 m
therefore 



Answer
Given,
Time period of star,T = 3.37 x 10⁷ s
Radius of circular orbit,R = 1.04 x 10¹¹ m
a) Angular speed of the planet

b) tangential speed

v = 1.94 x 10⁴ m/s
c) centripetal acceleration magnitude

a = 3.62 x 10⁻³ m/s²