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Rudik [331]
3 years ago
14

A sample of aluminum absorbed 9.86 J of heat and its temperature increased from 23.2 and 30.5 degrees * C . What is the mass of

the aluminum? Th specific heat of aluminum is 0.902 J/g^ C . Round your answer to 2 significant figures. Do not include units in your answer. *
Chemistry
1 answer:
Sidana [21]3 years ago
4 0

Explanation:

H=mc×∆©

9.86=m×0.902×(30.5-23.2)

m=1.5

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