The answer is A, do you want me to explain it? It’s pretty simple, you just need to follow all the signs in brackets and match them in those in the answer

7 0

2 years ago

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5. What is the mass of 9.80 x 1023 formula units of zinc chlorate, Zn(CO3)2?

Zielflug [23.3K]

Answer:

$\boxed{\text{378 g}}$

Explanation:

We must convert formula units of Zn(ClO₃)₂ to moles and then to grams of Zn(ClO₃)₂.

Step 1. Convert formula units to moles

$\text{Moles of Zn(ClO$_{3}$)$_{2}$}\\\\= 9.80 \times10^{23}\text{ formula units Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}{6.022 \times\ 10^{23} \text{ formula units Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$}$

Step 2. Convert moles to grams

$\text{Mass of Zn(ClO$_{3}$)$_{2}$}\\\\= \text{1.627 mol Zn(ClO$_{3}$)$_{2}$} \times \dfrac{\text{232.29 g Zn(ClO$_{3}$)$_{2}$}}{\text{1 mol Zn(ClO$_{3}$)$_{2}$}}\\\\= \text{378 g Zn(ClO$_{3}$)$_{2}$}\\\\\text{The mass of Zn(ClO$_{3}$)$_{2}$ is } \boxed{\textbf{378 g}}$

5 0

2 years ago

Write a balanced net ionic equation to show why the solubility of Cu(OH)2(s) increases in the presence of a strong acid and calc

Helga [31]

Answer:

2.2×10^8

Explanation:

Cu(OH)2(s)<---------> Cu^2+(aq) + 2OH^-(aq) Ksp=2.2 x 10 ^-20

2H3O^+(aq) + 2OH^-(aq) <-------> 4H2O(l). Kw= 1×10^14

Cu^2+(aq) + 4H2O(l) <--------> [Cu(H2O)4]^2+(aq)

Overall ionic reaction:

Cu(OH)2(s) +2H3O^+(aq) <---------> [Cu(H20)4]^2+(aq)

Equilibrium constant for the reaction: Ksp×Kw= 2.2 x 10 ^-20 × (1/(1×10^-14))^2

Keq= 2.2×10^8

Kw= ion dissociation constant of water

3 0

2 years ago