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3 years ago

You read a primary source and a secondary source that discuss the same

Chemistry

2 answers:

Serhud [2]3 years ago

8 0

Answer:

It depends on secondary sources and references of that secondary source. If it references just that primary source I would compare both of them and see the difference between them. Generally primary sources are more reliable but this situation is different.

shutvik [7]3 years ago

4 0

Answer:

i think it's D tbh, just cus it was the scientist who did the work

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1) These are barrel shaped microtubules in most animal cells, that organize the spindles during cell division

UNO [17]

The correct answer is "Centioles"

8 0

3 years ago

Non-electrolyte = A, 10.6 grams, dissolved in solvent B, 740 grams, the boiling point of the solution is higher than the boiling

Thepotemich [5.8K]

Answer:

2.1 °C/m

Explanation:

Hello, for this exercise, consider the formula:

$T_{solution}-T{solvent}=K_bm_solute$

Considering that the difference in the temperature is 0.284°C, and the given molality by:

$m_{solute}=\frac{10.6g\frac{1mol}{106g}}{740g*\frac{1kg}{1000g} } \\m_{solute}=0.135m$

Now, solving for $K_b$ , we get:

$K_b=\frac{0.284C}{0.135m}\\K_b=2.1 C/m$

Best regards.

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3 years ago

Incomplete dash of fuels produces many poisonous dash

tangare [24]

Answer:

Incomplete combustion of fuels produces a very poisonous gas called carbon monoxide:Excessive inhaling of carbon dioxide gas can kill a person.

I don't know if this is correct, your question did not have much context.

6 0

3 years ago

Identify the white color precipitate that forms when k2so4(aq) and pb(no3)2(aq) are mixed.

bekas [8.4K]

Here's your balanced chemical equation:

Pb(NO3)2 (aq) + K2SO4 (aq) ⇒ PbSO4 (s) + 2KNO3 (aq)

Therefore the precipitate formed is lead(II) sulfate.

3 0

3 years ago

Read 2 more answers

According to Markovnikov's rule of the electrophilic addition to an alkene, the electrophile, usually a proton, is more likely t

Natali [406]

Answer:

Explanation:

To fill in the gaps with the appropriate words, we need to rewrite the whole text in the question while adding the right answers to it.

$According \ to \ Markovnikov's \ rule \ of \ the \ electrophilic \ addition \ to \ an \ alkene, \\ \\ the \ electrophile, \ usually, \ a \ proton, \ is \ more \ likely \ to \ add \ to \ the \ \mathbf{less \ substituted \ carbon} \\ \\ \ in \ a \ double \ bond.$

$This \ arrangement \ place \ the \ intermediate \ carbocation \ on \ the \ \mathbf{more \ substituted \ carbon.}$ $Which \ stabilizer \ it \ with \ the\ presence \ of \ \mathbf{more \ substituents} \ the \ major \ product \ of$

$the \ reaction \ following \ markovnikov \ rules \ the \ \mathbf{nucleophile} \ will \ then \ end \ up$

$with \ the \ m ore \ substituted \ carbon \ in \ the \ double \ bond.$

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3 years ago