Answer:
- NH₄CN,
- NH₄ClO₃,
- (NH₄)₂SO₃,
- NH₄H₂PO₄.
- Al(CN)₃,
- Al(ClO₃)₃,
- Al₃(SO₃)₃,
- Al(H₂PO₄)₃.
Explanation:
Cations (positive ions) and anions (negative ions) combine to form ionic compounds. The charge of each ion is stated as the superscript in its formula.
The final compounds should be neutral (not carrying charge.) For that to happen, the ions should combine at a ratio that allows their charges to balance.
By convention, in chemical formula of ionic compounds, cations are written before anions.
<h3>Example: Al³⁺ and SO₃²⁻</h3>
The charge on an Al³⁺ cation is +3. The charge on a SO₃²⁻ anion is -2.
Start by finding the least common multiple of the absolute value of the charges (drop the negative sign in front of the charge.)
.
The number of Al³⁺ ions in a formula unit of this compound will be equal to
.
Similarly, the number of SO₃²⁻ ions in a formula unit of this compound will be equal to
.
If a polyatomic ion (an ion with more than one atoms in it) appears more than once in the formula, enclose it in brackets and write the number of its occurrence outside the bracket.
.
Apply this rule to find the formula of other compounds. Additionally, keep in mind that if the charge on the cation and the anion is the same, each should occur only once in the formula.
I think B
STEP-by STEP EXPLANATION
For a and b, you need to divide it by Avogadro’s number to find the answer.
a. (6.022x10^23)/6.022x10^23 = 1 mole of Ne
b. (3.011x10^23)/6.022x10^23 = 0.5 moles of Mg
For c and d, you’ll use the mass provided divided by the molar mass to find the number of moles.
Pb molar mass = 207.2 g/mol
c. (3.25x10^5)/207.2 = 1.57x10^3 moles of Pb
For d, I can’t tell if is Cu, C or something else but you can follow the steps above to solve the problem.
Explanation:
The condensed formula of a molecule is the formula where the symbols of atoms are listed in order as they appear in the molecule's structure with bond dashes omitted or limited.
The structural formular however, showed how the atoms are connected.
The condensed formular is given as; HOCH2COCH2OH
The condensed formular was gotten by writting out the elemnts in the order that they appear in.
The stuctural formular is shown in the attachement.