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kati45 [8]
2 years ago
10

A bus is traveling at 40 m/s after 5 seconds it comes to a stop what is the acceleration of the bus

Physics
1 answer:
WITCHER [35]2 years ago
3 0

Answer:

The acceleration becomes zero as it stops. It no longer moves

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Two concrete spans of a 380 m long bridge are
Mazyrski [523]

Answer:

4.163 m

Explanation:

Since the length of the bridge is

L = 380 m

And the bridge consists of 2 spans, the initial length of each span is

L_i = \frac{L}{2}=\frac{380}{2}=190 m

Due to the increase in temperature, the length of each span increases according to:

L_f = L_i(1+ \alpha \Delta T)

where

L_i = 190 m is the initial length of one span

\alpha =1.2\cdot 10^{-5} ^{\circ}C^{-1} is the temperature coefficient of thermal expansion

\Delta T=20^{\circ}C is the increase in temperature

Substituting,

L_f=(190)(1+(1.2\cdot 10^{-5})(20))=190.0456 m

By using Pythagorean's theorem, we can find by how much the height of each span rises due to this thermal expansion (in fact, the new length corresponds to the hypothenuse of a right triangle, in which the base is the original length of the spand, and the rise in heigth is the other side); so we find:

h=\sqrt{L_f^2-L_i^2}=\sqrt{(190.0456)^2-(190)^2}=4.163 m

4 0
3 years ago
A force of 1 N will cause a mass of 1 kg to have an acceleration of 1 m/s2. Therefore, a force of 7 N applied to a mass of 7 kg
Lana71 [14]

1 m/s^2

Using F=ma,

7=7a

a=1

3 0
2 years ago
Read 2 more answers
Hi i have homework can you help me
soldier1979 [14.2K]

Explanation:

The particle will be at rest when its velocity v(t) is equal to zero. Recall that the velocity is simply the derivative of the position x(t) with respect to time:

v(t) = \dfrac{dx}{dt}

Since x(t) = t^2 - 2t + 2

then

v(t) = \dfrac{d}{dt}(t^2 - 2t + 2) = 2t - 2 = 0

Solving for t, we find that the particle will be at rest at

t = 1\:\text{s}

6 0
2 years ago
The change from a solid to a liquid occurs at _____.
NNADVOKAT [17]
At the melting point
8 0
3 years ago
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A convex mirror has a focal length of 15cm. If the object is 35cm from the mirror and is 2cm tall, what is the magnification? Ro
Verizon [17]

Answer:

The magnification is 0.3

Explanation:

Given:

The focal length of the convex mirror, f = 15 cm

for convex mirror f = -f = -15 cm

The distance of object, u = 35 cm

Height of the object, h = 2 cm

Now, using the mirror formula, we have

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

where, v is the distance of the image

on substituting the values, we get

\frac{1}{-15}=\frac{1}{35}+\frac{1}{v}

or

-\frac{1}{v}=\frac{1}{35}-\frac{1}{-15}

or

v = -10.5 cm

now, the magnification (m) is given as:

m = -\frac{v}{u}

on substituting the values, we get

m = -\frac{-10.5}{35}

or

m = 0.3

Hence, the magnification is 0.3

6 0
2 years ago
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