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2 years ago

Hii so I am out of town unable to do this for my class can you guys use things in your own home? I will BRAINLIST!!1

Physics

2 answers:

ExtremeBDS [4]2 years ago

7 0

1.)t.v
2.) tablet
3.)nightstand
4.) led lights
5.) soft pillow
That’s all I can think of because I don’t have a lot

Luda [366]2 years ago

6 0

1. bed
2. tv
3. phone
4. chair
5. desk
6. couch
7. toilet
8. bathtub
9. lamp
10. night stand
11. blinds
12. curtains
13. candles
14. pens
15. blankets
16. pillows
17. earbuds
18. soap
19. fan
20. air conditioning

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a force of 50 newtons pulls a rope attached to a 150 newton sled across a horizontal surface at a constant velocity of 5 meters

lakkis [162]

Answer:

I don't know the answer I hope you find it tho good luck##

3 0

2 years ago

Jessica has a mass of 55kg she sleds down a hill that has a slope of 32 degrees. what is the component of her weight that is alo

Arturiano [62]

Answer:

W = 285.62 N

Explanation:

It is given that,

Mass of Jessica is 55 kg

Slope of the hill is 32 degrees

We need to find the component of her weight that is along her direction of motion.

The component along her direction of motion is shown in attached figure. It means

$W_y=mg\sin\theta\\\\W_y=55\times 9.8\times \sin(32)\\\\W_y=285.62\ N$

So, the component of her weight that is along her direction of motion is 285.62 N.

7 0

3 years ago

Read 2 more answers

A force of 20 N produces an acceleration of 10 m/s² in mass m1 and an acceleration of 5 m/s² in

Scrat [10]

Explanation:

F = 20N m= m1 a=10m/s²

m=m2 a=5m/s²

F = ma

for the first one: 

f=m1 × a

20 = m1 ×10

20=10m1

m1=20/10

m1=2

for the second one :

f=m2×a

20=m2×5

m2= 20/5

m2= 4

since F=ma

F=(m1+m2) ×a

F =(4+2)×a

F =6×a

F=20(from the question above )

20=6×a

a=20/6

a=3.33

8 0

3 years ago

Read 2 more answers

Un camion de envios se encuentra detenido en una señal de pare, permitiendo que pase una ambulancia. Inicia su recorrido y al ca

Nesterboy [21]

Answer:

$0.741\ \text{m/s}^2$

Explanation:

v = Velocidad final = $40\ \text{km/h}=\dfrac{40}{3.6}\ \text{m/s}$

u = Velocidad inicial = 0

t = Tiempo empleado = 15 s

a = Aceleración

De las ecuaciones cinemáticas tenemos

$v=u+at\\\Rightarrow a=\dfrac{v-u}{t}\\\Rightarrow a=\dfrac{\dfrac{40}{3.6}-0}{15}\\\Rightarrow a=0.741\ \text{m/s}^2$

La aceleración del camión en el primer intervalo de tiempo es $0.741\ \text{m/s}^2$ .

4 0

3 years ago

Imagine you’re driving along a road and you approach a bridge. You notice a sign that reads, “Bridge freezes before road.” Why d

nydimaria [60]

Answer:

<h3>During wet and freezing temperatures, ice is able to form at a faster pace on bridges because freezing winds blow from above and below and both sides of the bridge, causing heat to quickly escape. The road freezes slower because it is merely losing heat through its surface.</h3>

Sources:

-- https://intblog.onspot.com/en-us/why-do-bridges-become-icy-before-roads

and

-- https://www.accuweather.com/en/accuweather-ready/why-bridges-freeze-before-roads/687262

I hope this helps you! ^^

6 0

2 years ago