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Karo-lina-s [1.5K]
3 years ago
14

4 applications of elasticity​

Physics
1 answer:
svet-max [94.6K]3 years ago
8 0

Answer:

elasticity

1.price elasticity of demand

2.income elasticity of demand

3.cross elasticity of demand

4.elasticity of supply

Explanation:

1. price elasticity of demand is the degree to which the effective desire for something changes as its price changes. In general, people desire things less as those things become more expensive.

2. income elasticity of demand is the responsiveness of the quantity demanded for a good to a change in consumer income. It is measured as the ratio of the percentage change in quantity demanded to the percentage change in income.

3. cross elasticity of demand or cross-price elasticity of demand measures the responsiveness of the quantity demanded for a good to a change in the price of another good, ceteris paribus.

4.price elasticity of supply is a measure used in economics to show the responsiveness, or elasticity, of the quantity supplied of a good or service to a change in its price.

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The quantity of ionising energy absorbed by 1 text kg1 kg of tissue is defined as a radiation dose Gy. While RBE is a measure of a specific dose's biological effect relative to the biological effect of an equal quantity of X rays.

<h3>What is radiation?</h3>

Radiation is energy that moves through space at the speed of light from a source. This energy is coupled with an electric and magnetic field, and it exhibits wave-like qualities. Radiation is sometimes known as "electromagnetic waves."

Nature has a diverse variety of electromagnetic radiation. One example is visible light.

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2 years ago
How fast does a 2 MeV fission neutron travel through a reactor core?
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Answer:

The answer is 1.956 \times 10^7\ m/s

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From the last equation,

v= \sqrt{2E/m}

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3 years ago
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KATRIN_1 [288]

Answer:

v = 7.4 m/s

Explanation:

Given that,

Mass if a volleyball, m = 5 kg

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We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 2.8} \\\\=7.4\ m/s

So, the required speed is 7.4 m/s. Hence, the correct option is (b).

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3 years ago
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Therefore, our answer will now be

K.E=2800000j

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