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3 years ago

4 applications of elasticity

Physics

1 answer:

svet-max [94.6K]3 years ago

8 0

Answer:

elasticity

1.price elasticity of demand

2.income elasticity of demand

3.cross elasticity of demand

4.elasticity of supply

Explanation:

1. price elasticity of demand is the degree to which the effective desire for something changes as its price changes. In general, people desire things less as those things become more expensive.

2. income elasticity of demand is the responsiveness of the quantity demanded for a good to a change in consumer income. It is measured as the ratio of the percentage change in quantity demanded to the percentage change in income.

3. cross elasticity of demand or cross-price elasticity of demand measures the responsiveness of the quantity demanded for a good to a change in the price of another good, ceteris paribus.

4.price elasticity of supply is a measure used in economics to show the responsiveness, or elasticity, of the quantity supplied of a good or service to a change in its price.

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What iz inertia ? -,-

kipiarov [429]

Inertia refers to the tendency of a body to resist changes.

<h3>Inertia</h3>

It is the property of a body to resist change.

A moving body will continue moving until a force acts on it. Unless the acting force is big enough to overcome the inertia of the body, the body will continue moving.

Also, a body at rest will continue resting unless a force big enough to overcome the inertia force is used to displace it.

More on inertia can be found here: brainly.com/question/1358512

4 0

2 years ago

Read 2 more answers

What is the current in a wire of radius R = 2.02 mm if the magnitude of the current density is given by (a) Ja = J0r/R and (b) J

Sloan [31]

Explanation:

For this problem we have to take into account the expression

J = I/area = I/(π*r^(2))

By taking I we have

I = π*r^(2)*J

(a)

For Ja = J0r/R the current is not constant in the wire. Hence

$I(r) = \pi r^{2} J(r) = \pi r^{2} J_{0}r/R = \pi r^{3} (3.74*10^{4}A/m^{2})/(2.02*10^{-3}m)$

and on the surface the current is

$I(R) = \pi r^{2} J(R) = \pi r^{2} J_{0}R/R = \pi(2.02*10^{-3})^{2} (3.74*10^{4}) = 0.47 A$

(b)

For Jb = J0(1 - r/R)

$I(r)=\pi r^{2}J(r) =\pi r^{2} J_{0}(1 - r/R)=\pi r^{2}J_{0}(1-\frac{r}{2.02*10^{-3}} )$

and on the surface

$I(R)=\pi r^{2}J_{0}(1-R/R)=\pi r^{2}J_{0}(1-1)= 0$

(c)

Ja maximizes the current density near the wire's surface

Additional point

The total current in the wire is obtained by integrating

$I_{T}=\pi\int\limits^R_0 {r^{2}Ja(r)} \, dr = \pi \frac{J_{0}}{R}\int\limits^R_0 {r^{3}} \ dr =\pi \frac{J_{0}R^{4}}{4R}=\frac{1}{4}\pi J_{0}R^{3}=2.42*10^{-4} A$

and in a simmilar way for Jb

$I_{T}=\pi J_{0} \int\limits^R_0 {r^{2}(1-r/R)} \, dr = \pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2R}]=\pi J_{0}[\frac{R^{3}}{3}-\frac{R^{2}}{2}]$

And it is only necessary to replace J0 and R.

I hope this is useful for you

regards

7 0

3 years ago

The current in a hair dryer measures 15 amps the resistance of the hair dryer is 8 ohms

suter [353]

The voltage at the input to the hair dryer is

V = (current) · (resistance)

V = (15 A) · (8 Ω)

V = 120 volts

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The power dissipated by the hair dryer is

P = (current)²· (resistance)

P = (15 A)² · (8 Ω)

P = 1800 watts

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3 years ago

What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?

Mice21 [21]

5.5 is the answer i think

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3 years ago

A sound wave has a frequency of 247 Hz and a wavelength of 1.4 m. What is the speed of the sound wave in air?

zavuch27 [327]

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3 years ago

4 applications of elasticity​

4 applications of elasticity