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Zinaida [17]
3 years ago
6

Name and describe at least SIX engineering challenges that the Mars copter, Ingenuity, had to overcome in order to be built/to t

ravel to Mars/to function on Mars. BE SPECIFIC with your answers!
Physics
1 answer:
Levart [38]3 years ago
4 0

Answer:

was possible, using an experimental aircraft," said Håvard Grip, Ingenuity’s chief pilot at NASA's Jet Propulsion Laboratory in Southern California. "With Ingenuity, we're trying to do the same for Mars."

Here are six things you should know about the first helicopter going to another planet:

1. Ingenuity is a flight test.

Ingenuity is what is known as a technology demonstration – a project that seeks to test a new capability for the first time, with limited scope. Previous groundbreaking technology demonstrations include the Mars Pathfinder rover Sojourner and the tiny Mars Cube One (MarCO) CubeSats that flew by Mars in 2018.

Ingenuity features four specially made carbon-fiber blades, arranged into two rotors that spin in opposite directions at around 2,400 rpm – many times faster than a passenger helicopter on Earth. It also has innovative solar cells, batteries, and other components. Ingenuity doesn't carry science instruments and is a separate experiment from the Mars 2020 Perseverance rover.

2. Ingenuity will be the first aircraft to attempt controlled flight on another planet.

NASA's Ingenuity Mars Helicopter will make history's first attempt at powered flight on another planet next spring. It is riding with the agency's next mission to Mars (the Mars 2020 Perseverance rover) as it launches from Cape Canaveral Air Force Station later this summer. Perseverance, with Ingenuity attached to its belly, will land on Mars February 18, 2021.

Credits: NASA/JPL-Caltech

What makes it hard for a helicopter to fly on Mars? For one thing, Mars' thin atmosphere makes it difficult to achieve enough lift. Because the Mars atmosphere is 99% less dense than Earth's, Ingenuity has to be light, with rotor blades that are much larger and spin much faster than what would be required for a helicopter of Ingenuity's mass on Earth.

It can also be bone-chillingly cold at Jezero Crater, where Perseverance will land with Ingenuity attached to its belly in February 2021. Nights there dip down to minus 130 degrees Fahrenheit (minus 90 degrees Celsius). While Ingenuity's team on Earth has tested the helicopter at Martian temperatures and believes it should work on Mars as intended, the cold will push the design limits of many of Ingenuity's parts.

In addition, flight controllers at JPL won't be able to control the helicopter with a joystick. Communication delays are an inherent part of working with spacecraft across interplanetary distances. Commands will need to be sent well in advance, with engineering data coming back from the spacecraft long after each flight takes place. In the meantime, Ingenuity will have a lot of autonomy to make its own decisions about how to fly to a waypoint and keep itself warm.

3. Ingenuity is a fitting name for a robot that is the result of extreme creativity.

High school student Vaneeza Rupani of Northport, Alabama, originally submitted the name Ingenuity for the Mars 2020 rover, before it was named Perseverance, but NASA officials recognized the submission as a terrific name for the helicopter, given how much creative thinking the team employed to get the mission off the ground.

"The ingenuity and brilliance of people working hard to overcome the challenges of interplanetary travel are what allow us all to experience the wonders of space exploration," Rupani wrote. "Ingenuity is what allows people to accomplish amazing things."

NASA's Mars 2020 Perseverance rover and NASA's Ingenuity Mars Helicopter (shown in an artist's concept)

In February 2021, NASA's Mars 2020 Perseverance rover and NASA's Ingenuity Mars Helicopter (shown in an artist's concept) will be the agency's two newest explorers on Mars. Both were named by students as part of an essay contest.

Credits: NASA/JPL-Caltech

Full image and caption

4. Ingenuity has already demonstrated feats of engineering.

In careful steps from 2014 to 2019, engineers at JPL demonstrated that it was possible to build an aircraft that was lightweight, able to generate enough lift in Mars' thin atmosphere, and capable of surviving in a Mars-like environment. They tested progressively more advanced models in special space simulators at JPL. In January 2019, the actual helicopter that is riding with Perseverance to the Red Planet passed its final flight evaluation. Failing any one of these milestones would've grounded the experiment.

5. The Ingenuity team will count success one step at a time.

Given the firsts Ingenuity is trying to accomplish, the team has a long list of milestones they'll need to pass before the helicopter can take off and land in the spring of 2021. The team will celebrate each time they meet one. The milestones include:

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Cylindrical beaker of height 0.100 mm and negligible weight is filled to the brim with a fluid of density rhorhorho = 890 kg/m3k
Nesterboy [21]

Incomplete part of the question

A ball of density ρb = 5000 kg/m3 and volume V = 60.0 cm3 is then submerged in the fluid, so that some of the fluid spills over the side of the beaker. The ball is held in place by a stiff rod of negligible volume and weight. Throughout the problem, assume the acceleration due to gravity is g = 9.81 m/s2 .  What is the weight Wb of the ball? Express your answer numerically in newtons.

What is the reading W2 of the scale when the ball is held in this submerged position? Assume that none of the water that spills over stays on the scale. Calculate your answer from the quantities given in the problem and express it numerically in newtons.

What is the force Fr applied to the ball by the rod? Take upward forces to be positive (e.g., if the force on the ball is downward, your answer should be negative). Express your answer numerically in newtons.

The rod is now shortened and attached to the bottom of the beaker. The beaker is again filled with fluid, the ball is submerged and attached to the rod, and the beaker with fluid and submerged ball is placed on the scale.

What weight W3 does the scale now show?

Answer:

(a) 2.94 N

(b) 1 N

(c) 2.42 N

(d) 3.42 N

Explanation:

(a)

From the definition of density, it's mass per unit volume hence mass is a product of density and volume. To get weight, we multiply mass by acceleration due to gravity

The weight of the ball is W=\rho g V

Where \rho is the density, V is volume and g is acceleration due to gravity

Substituting density for 5000 Kg/m3 and g for 9.8 m/s2 and v for 0.00006 m3 then

W= 5000 kg/m^{3} * 9.8 m/s^{2} * 0.00006 m^{3}=2.94 N

(b)

Because the ball is being held up mostly by the rod, the fluid pressure on the bottom of the cylinder is just the same as before.

The scale does not "know" the ball is there at all.

That's why it still reads 1 N.

Therefore, the reading is 1 N

(c)

The buoyant force of the fluid on the ball is equal to the weight of the displaced fluid, namely,

890 kg/m^{3} * 9.8 m/s^{2} * 0.00006 m^{3} = 0.52 N

so the force needed for the rod to hold up the ball is 2.94 N - 0.52 N = 2.42 N.

(d)

Now the scale "feels" the weight of the ball,

so the scale reads the weight of the ball

PLUS the weight of the original fluid

MINUS the weight of the fluid that was displaced

= 2.94 N + 1.00 N - 0.52 N = 3.42 N

6 0
3 years ago
A 1,200 kg subcompact car accelerates at a rate of 3.0m/s
ludmilkaskok [199]
Missing question (found on internet): 
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Solution:
According to Newton's second law, the force of the car is equal to the product between its mass and its acceleration:
F=ma
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m=1200 kg
a=3.0 m/s^2
So the force that accelerates the car is
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3 years ago
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ICE Princess25 [194]

(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

For (b): Use the formula for distance (s) made during an accelerated motion:

s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2

with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case  solely due to gravitational acceleration so: "g."

You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.

For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion

(velocity at time t) = (acceleration) x (time)  

again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).  

If my calculation is correct, this mystery planet could be the Jupiter.


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4 years ago
A forward honzontal force of 50 N is applied to a crate. A second horizontal force o
True [87]

Answer:

Explanation:

magnitude: 180-50=130N

Direction: in the direction same as the second horizontal force

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What happens when a wave encounters a boundary and then goes back to the original medium?
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It causes a movement of convection in the water resulting in a pulling current.

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