Answer:
Present in both catabolic and anabolic pathways
Explanation:
Glyceraldehyde-3-phosphate abbreviated as G3P occurs as intermediate in glycolysis and gluconeogenesis.
In photosynthesis, it is produced by the light independent reaction and acts as carrier for returning ADP, phosphate ions Pi, and NADP+ to the light independent pathway. Photosynthesis is a anbolic pathway.
In glycolysis, Glyceraldehyde-3-phosphate is produced by breakdown of fructose-1,6 -bisphosphate. Further Glyceraldehyde-3-phosphate converted to pyruvate and pyruvate is further used in citric acid cycle for energy production. Therefore, it is used in catabolic pathway too.
Glyceraldehyde-3-phosphate is an important intermediate molecule in the cell's metabolic pathways because it is present in both catabolic and anabolic pathways.
Answer:
When a mixture of methane and chlorine is exposed to ultraviolet light - typically sunlight - a substitution reaction occurs and the organic product is chloromethane. CH 4 + Cl 2 → CH 3 Cl + HCl However, the reaction doesn't stop there, and all the hydrogens in the methane can in turn be replaced by chlorine atoms.
Explanation:
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Answer:
When an organism dies, it is usually destroyed by other forms of life and by weathering processes. On rare occasions some body parts—particularly hard ones such as shells, teeth, or bones—are preserved by being buried in mud or protected in some other way from predators and weather. Eventually, they may become petrified and preserved indefinitely with the rocks in which they are embedded. Methods such as radiometric dating—measuring the amounts of natural radioactive atoms that remain in certain minerals to determine the elapsed time since they were constituted—make it possible to estimate the time period when the rocks, and the fossils associated with them.
Answer:
There is no choices to choose from
Answer:
a) Molarity = 0.199M
b) 21.6L of solution
c) 0.199 moles of sucrose in 1L
Explanation:
a) Molarity is the ratio of moles of solute (sucrose) in volume of solution (3.30L):
<em>Moles sucrose -Molar mass: 342,3g/mol-:</em>
225.0g * (1mol / 342,2965g) = 0.6573 moles
Molarity = 0.6573 moles / 3.30L
<h3>Molarity = 0.199M</h3><h3 />
b) 0.199M means 0.199 moles in 1L. 4.30 moles are in:
4.30 mol * (1L / 0.199mol) = 21.6L of solution
c) By definition, there are 0.199 moles of sucrose in 1L. This is the meaning of 0.199M