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Anon25 [30]
3 years ago
11

In which area of the sun does gas rise as it heats up, then fall back down as it cools

Physics
2 answers:
Phoenix [80]3 years ago
7 0

Answer:

The convective zone.

Marrrta [24]3 years ago
4 0
Convection Zone: Just beneath the photosphere, and extending inward to about 0.7 Rsun, is the convection zone. Energy generated in the core of the Sun moves outward through this layer by a boiling motion in which hot plasma rises, releases some of its energy, cools, and then sinks again.
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What is the z coordinate for the above vector?
Hitman42 [59]
120 m would be he answer
4 0
3 years ago
Two identical charges, each -8.00 E-5 C, are separated by a distance of 20.0 cm (100 cm = 1 m). What is the force of repulsion?
Rom4ik [11]

F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.

The easiest way to solve this problem is using Coulomb's Law given by the equation F=k\frac{|q_{1}*q_{2}|}{r^{2} }, where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.

We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.

First, we have to convert 20.0 cm to meters.

(20.0 cm x 1m)/100cm = 0.20 m

Using the Coulomb's Law equation:

F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}} \frac{|-8.00x10^{-5}C*-8.00x10^{-5}C|}{(0.20m)^{2} }

F = 9.00x10^{9}\frac{Nm^{2}}{C^{2}}(1.6x10^-7\frac{C^{2} }{m^{2} } })\\F = 1440N

5 0
3 years ago
*100 points, please do all if not most of the questions listed, thank you*
e-lub [12.9K]

Answer:

1a.5km

2a. 31536000 seconds

2b.2800000 centimeters

2c.45,000,000 Milligrams

2d.0.0141667 m/s

2e.2.592 x 10^10 km/day

2f .8.23x10^-7m

2g.0.0000085 m3

Explanation:

1a.(25km/5)(1000m/1km)(1h/3600s) =(5km)( 1) (1) =5km

pls mark as brainliest

3 0
3 years ago
Which two technologies use the same range of radio wave frequencies? television broadcasting and AM radio broadcasting cell phon
Tju [1.3M]
Let us reject some answers. AM and FM radio waves do not interfere. Am are an orders of magnitude larger than FM waves. FM waves belong to microwaves, a subcategory of radiowaves while AM does not. Similarly, AM  and TV have not the same, because TV uses a subset of the frequencies used in FM. The correct answe is that CB radios and submarine communication happen at the same wavelengths/frequencies, namely low frequency radiowaves.
4 0
3 years ago
Read 2 more answers
que tiempo tarda juan en su carro al llegar al trabajo si lleva una velocidad de 25 m/s a una distancia de 5m
kramer

Answer:

0.2s

Explanation:

Given parameters:

Speed  = 25m/s

Distance  = 5m

Unknown:

Time taken for Juan to get to his work  = ?

Solution:

To solve this problem we use the relationship below:

 

   Speed  = \frac{distance}{time}  

  Time  =  \frac{distance }{speed}  

So;

   Time  = \frac{5}{25}   = 0.2s

4 0
3 years ago
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