F = 1440 N. The repulsion force between two identical charges, each -8.00x10⁻⁵C separated by a distance of 20.0 cm is 1440 N.
The easiest way to solve this problem is using Coulomb's Law given by the equation
, where k is the constant of proportionality or Coulomb's constant, q₁ and q₂ are the charges magnitude, and r is the distance between them.
We have to identical charges of -8.00x10⁻⁵C, are separated by a distance of 20.0 cm, and we need to know the force of repulsion between the charges.
First, we have to convert 20.0 cm to meters.
(20.0 cm x 1m)/100cm = 0.20 m
Using the Coulomb's Law equation:


Answer:
1a.5km
2a. 31536000 seconds
2b.2800000 centimeters
2c.45,000,000 Milligrams
2d.0.0141667 m/s
2e.2.592 x 10^10 km/day
2f .8.23x10^-7m
2g.0.0000085 m3
Explanation:
1a.(25km/5)(1000m/1km)(1h/3600s) =(5km)( 1) (1) =5km
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Let us reject some answers. AM and FM radio waves do not interfere. Am are an orders of magnitude larger than FM waves. FM waves belong to microwaves, a subcategory of radiowaves while AM does not. Similarly, AM and TV have not the same, because TV uses a subset of the frequencies used in FM. The correct answe is that CB radios and submarine communication happen at the same wavelengths/frequencies, namely low frequency radiowaves.
Answer:
0.2s
Explanation:
Given parameters:
Speed = 25m/s
Distance = 5m
Unknown:
Time taken for Juan to get to his work = ?
Solution:
To solve this problem we use the relationship below:
Speed =
Time =
So;
Time =
= 0.2s