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Anon25 [30]
3 years ago
11

In which area of the sun does gas rise as it heats up, then fall back down as it cools

Physics
2 answers:
Phoenix [80]3 years ago
7 0

Answer:

The convective zone.

Marrrta [24]3 years ago
4 0
Convection Zone: Just beneath the photosphere, and extending inward to about 0.7 Rsun, is the convection zone. Energy generated in the core of the Sun moves outward through this layer by a boiling motion in which hot plasma rises, releases some of its energy, cools, and then sinks again.
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Darwin observed fossils of glyptodonts, which are now extinct. Living armadillos are the only animals remaining on Earth that ar
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Answer:

3. Glyptodons were early relatives of armadillos.

Explanation:

Darwin would have come to this conclusion because glyptodons over time became armadillos, which you can tell by evolution that they were better evolved to survive than glyptodons. Due to this, they outlived the glyptodons.

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3 years ago
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Tyra made the following bar graph shown to represent the relative distances of four different astronomical bodies from Earth.
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4 years ago
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A Hooke's law spring is mounted horizontally over a frictionless surface. The spring is then compressed a distance d and is used
zloy xaker [14]

Answer:

The compression is \sqrt{2} \  d.

Explanation:

A Hooke's law spring compressed has a potential energy

E_{potential} = \frac{1}{2} k (\Delta x)^2

where k is the spring constant and \Delta x the distance to the equilibrium position.

A mass m moving at speed v has a kinetic energy

E_{kinetic} = \frac{1}{2} m v^2.

So, in the first part of the problem, the spring is compressed a distance d, and then launch the mass at velocity v_1. Knowing that the energy is constant.

\frac{1}{2} m v_1^2 = \frac{1}{2} k d^2

If we want to double the kinetic energy, then, the knew kinetic energy for a obtained by compressing the spring a distance D, implies:

2 * (\frac{1}{2} m v_1^2) = \frac{1}{2} k D^2

But, in the left side we can use the previous equation to obtain:

2 * (\frac{1}{2} k d^2) = \frac{1}{2} k D^2

D^2 =  \frac{2 \ (\frac{1}{2} k d^2)}{\frac{1}{2} k}

D^2 =  2 \  d^2

D =  \sqrt{2 \  d^2}

D =  \sqrt{2} \  d

And this is the compression we are looking for

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3 years ago
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