The atomic number of a neutral atom is equal to the number of protons and the number of electrons of the atom. The atomic weight meanwhile is equal to the sum of the number of protons and number of neutrons. In this case, the no.of protons is 19 and the number of neutrons is 40-19 equal to 21.
The solubility of sodium nitrate at 95º C in g/ 100 mL of water is 448.21.
<h3>Equation :</h3>
To calculate the solubility
Using formula,
Solubility = mass of the compound / mass of the solvent
Thus,
Known data is :
mass of the compound, sodium nitrate = 84.994 g/mol
mass of the solvent, water = 18.015 g/mol
C = 84.994 g/mol / 18.015 g/mol
C = 4.718 g/mol
By the temperature 95ºC
So,
C = 4.718 g/mol x 95ºC
C = 448.21 g/ 100 mL
<h3>Solubility :</h3>
The maximum amount of the sample that will dissolve in a given amount of solvent at a given temperature is referred to as its solubility. Different substances have very different solubilities, which is a characteristic of a particular solute-solvent combination.
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As your body needs more oxygen during exercising and produces more carbon dioxide, this might result in a high respiratory rate.
During exercise, your breathing may occur 3–4 times more frequently. Hyperpnea, or rapid, deep breathing, is the body's natural response to increased carbon dioxide generation. The pace of breathing increases along with the blood's concentration of carbon dioxide. The pH of the blood changes dramatically as carbon dioxide levels rise. The chemoreceptors in the medulla oblongata, a part of the hindbrain that controls respiration, detect this shift. To expel the additional carbon dioxide and breathe in more oxygen, the respiratory center speeds up breathing.
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<span>Acetic acid is under the family
of carboxylic acids which has a carboxyl group –COOH bond attached to the alkyl
group. Alkyl group can be methyl (CH3-), ethyl (CH3CH2-) and so on. The term
acetic also means methyl. So combining the two gives CH3COOH or HCH3CO2. The H
before the C in <u>H</u>CH3CO2 means that it is the H attached to the O in the carboxyl
group –COOH. You cannot write it as C2H4O2 because it would represent a
different compound.</span>