Answer:
(C5H7)8
Explanation:
It's empirical formula is given as; C5H7
Molar mass of carbon(C) = 12 g/mol
Molar mass of hydrogen(H) = 1 g/mol
We are told that it's molar mass is 536 g/mol.
To find the molecular formula;
Molecular formula = n × empirical formula
Thus;
n = 536/((12 × 5) + (1 × 7))
n = 8
Thus;
Molecular formula = (C5H7)8
<span>Molar mass is the mass of
one mole of a substance, it can be a chemical element or a compound. It is a
characteristic of each pure substance. We calculate it by adding up all of the masses of the atoms involved in the compound. We calculate as follows:
atomic mass total mass
C 17 12.01 g/mol 204.17 g/mol
H 19 1.01 g/mol 19.19 g/mol
N 1 14.00 g/mol 14.00 g/mol
O 3 16.00 g/mol 48.00 g/mol
------------------------------------------------------------
Molar mass = 285.36 g/mol
</span><span>What is the mass of 6.02 x 10^24 molecules of morphine?
</span>6.02 x 10^24 molecules ( 1 mol / 6.02x10^23 molecules) ( 285.36 g/mol) = 2853.6 g morphine
The number of atoms N = 5.8 x 10²¹
<h3>Further explanation</h3>
A mole is a unit of many particles (atoms, molecules, ions) where 1 mole is the number of particles contained in a substance that is the same amount as many atoms in 12 gr C-12
1 mole = 6.02.10²³ particles
mass of N in 0.82 g of NaNO₃ (MW NaNO₃: 85 g/mol) :

moles of N :

The number of atoms N :

2 im pretty sure but im not for sure
Answer:
D . 20 grams reactant U + 3 grams reactant V → 23 grams product W
Explanation:
Law of conservation of mass states:
The mass of a closed system (As a reaction), is neither created or destroyed.
That is, the mass of reactants is equal to mass of products.
A. In reaction A 22g of reactants produce 9g of products. This reaction doesn't illustrates the law of conservation of mass.
B. 10g reactant produce 25g of products. This reaction doesn't illustrates the law of conservation of mass.
C. 19g of reactants produce 180g of products. This reaction doesn't illustrates the law of conservation of mass.
D. 23g of reactants produce 23g of products. -This is the reaction that best illustrates the Law of Conservation of Mass.