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algol [13]
2 years ago
13

A boy standing at one end of a floating raft that is stationary relative to the shore walks to the opposite end of the raft, awa

y from shore. As a consequence, the raft (a) remains stationary, (b) moves away from the shore, or (c) moves toward the shore. (Hint: Use Conservation of Momentum)
Physics
1 answer:
kaheart [24]2 years ago
6 0

Answer:

(c) moves toward the shore.

Explanation:

Momentum can be defined as the multiplication (product) of the mass possessed by an object and its velocity. Momentum is considered to be a vector quantity because it has both magnitude and direction.

Mathematically, momentum is given by the formula;

Momentum = mass * velocity

The law of conservation of momentum states that the total linear momentum of any closed system would always remain constant with respect to time.

In this scenario, a boy standing at one end of a floating raft that is stationary relative to the shore walks to the opposite end of the raft, away from shore. As a consequence, the raft moves toward the shore because the momentum of the closed system (boy and raft) has a zero magnitude and would remain constant.

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which type of graph shows data seperated into intervals? A. stemplot B. Line Graph C. Scatterplot D. Histogram
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A histogram with equal intervals is suitable here.

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Describe a well-known hypothesis that was discarded because it was found to be untrue.earth-centered model of the universe. the
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The city is thinking about starting a program to add a new chemical to the public pool. Before they do, they want to find out if
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4 0
3 years ago
What is the mass of an object that has a weight of 2867 N?
Gnom [1K]

Answer:

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7 0
2 years ago
if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

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r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

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3 years ago
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