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2 years ago

Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its

Engineering

1 answer:

kirill115 [55]2 years ago

3 0

<h2>Answer:</h2>

<h3>Required Answer is as follows :-</h3>

$\sf \dfrac{P _{i}}{ P_{f}} = \dfrac{3}{4}$

3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

¾ = m₁ × (V)²/m₂ × (V²/4)

¾ = m₁/m₂ × 4

m₂ = 4 × 4/3 = 16/3m₁

$\bold{ }$

∆m = m₂ - m₁
∆m = 16m₂/3 - m₁ = 13m₁/3
Ratio = (13m₁/3)/ m₁
Ratio = 13/3

Ratio = 13:3

$\bold{ }$

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg. $\bold{ }$

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2 years ago

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navik [9.2K]

Answer:

(a) 561.12 W/ m² (b) 196.39 MW

Explanation:

Solution

(a) Determine the energy and power of the wave per unit area

The energy per unit are of the wave is defined as:

E = 1 /16ρgH²

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=3927. 83 J/m²

Thus,

The power of the wave per unit area is,

P = E/ t

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(b) The average and work power output of a wave power plant

W = E * л * A

= 3927. 83 J/m² * 0.35 * 1 *10^6 m²

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2 years ago

For automobile engines, identify the best choice of motor oil.

Vlad1618 [11]

Answer:

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Explanation:

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In winter climates, we should use oil with low viscosity as at lower temperatures, the it flows more readily if its viscosity is low.

But the summer season needs a relatively thicker oil so as to reduce the thinning effect of the oil out of the engine.

Thus for Maine in the winter season, we need a low viscosity oil and for Florida a high viscosity oil in the summer season.

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2 years ago

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Answer:

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Explanation:

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3 years ago

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