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Mama L [17]
3 years ago
6

Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its

Engineering
1 answer:
kirill115 [55]3 years ago
3 0

<h2>Answer:</h2>

<h3>Required Answer is as follows :-</h3>

  • \sf \dfrac{P _{i}}{ P_{f}} = \dfrac{3}{4}

  • 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

  • ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

  • ¾ = m₁ × (V)²/m₂ × (V²/4)

  • ¾ = m₁/m₂ × 4

  • m₂ = 4 × 4/3 = 16/3m₁

\bold{   } 

<h3>Now,</h3>
  • ∆m = m₂ - m₁
  • ∆m = 16m₂/3 - m₁ = 13m₁/3
  • Ratio = (13m₁/3)/ m₁
  • Ratio = 13/3

Ratio = 13:3

\bold{   } 

<h3>Know More :-</h3>

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.\bold{   } 

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8 0
3 years ago
The Cv factor for a valve is 48. Compute the head loss when 30 GPM of water passes through the valve.
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Answer:

The head loss in Psi is 0.390625 psi.

Explanation:

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Given:

Factor cv is 48.

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GPM means gallon per minute.

Calculation:

Step1

Expression for head loss for the water is given as follows:

c_{v}=\frac{Q}{\sqrt{h}}

Here, cv is valve coefficient, Q is flow rate in GPM and h is head loss is psi.

Step2

Substitute 48 for cv and 30 for Q in above equation as follows:

48=\frac{30}{\sqrt{h}}

{\sqrt{h}}=0.625

h = 0.390625 psi.

Thus, the head loss in Psi is 0.390625 psi.

 

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Explanation:

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