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Likurg_2 [28]
3 years ago
7

WHICH ONE DO YOU LIKE *CREDIT 2 sbrianna3606*

Engineering
1 answer:
RSB [31]3 years ago
6 0

Answer:

first one, rest are okay ig.....

Explanation:

You might be interested in
Terri Duncan recommends following up after an interview in which way?
Varvara68 [4.7K]

Answer:

make contact in a way which fits the industry and is comfortable to you

Explanation:

Terri Duncan was a person that helped people going for interviews by offering them professional advice on how to compose and conduct themselves during an interview.

Terri Duncan also helps people going for interviews but providing them with the aid they need concerning what to say during an interview.

Terri Duncan recommends following up after an interview by making contact in a way which fits the industry and is also comfortable to you.

3 0
3 years ago
One proposed technique to reduce outage probability is to use macrodiversity, where a mobile unit’s signal is received by multip
NARA [144]

Answer:

This might reduce outage probability because multiple base stations are able to receive a given mobile signal at a time which lead to signal outage decrease or weakness.

5 0
4 years ago
A direct-coupled amplifier has a low-frequency gain of 40 dB, poles at 2 MHz and 20 MHz, a zero on the negative real axis at 200
rewona [7]

Answer:

Explanation:

Low frequency gain is= 40db= 20logK=>100 poles at 2MHz,20MHz

Zero at -200MHz, zero at infinity.

A) A(s) = 100FH(s)

B) Poles (1): 2 pi × 2 × 10^6= 4pi × 10^6MHz

              (2): 2pi × 20 × 10^6= 4pi × 10^6 MHz

 Zeroed: 2pi × 10^6 × 200= 400pi × 10^6, at infinity.

T/(S) = (1 + S/400π × 10^6)/S(1 + S/4π × 10^6)(1 + S/4π × 10^6)

8 0
3 years ago
1. The sine rule is used when we are given either a) two angles and one side, or b) two sides and a non-included angle.
sammy [17]

Answer:

A. Yes

B. Yes

Explanation:

We want to evaluate the validity of the given assertions.

1. The first statement is true

The sine rule stipulates that the ratio of a side and the sine of the angle facing the side is a constant for all sides of the triangle.

Hence, to use it, it’s either we have two sides and an angle and we are tasked with calculating the value of the non given side

Or

We have two angles and a side and we want to calculate the value of the side provided we have the angle facing this side in question.

For notation purposes;

We can express the it for a triangle having three sides a, b, c and angles A,B, C with each lower case letter being the side that faces its corresponding big letter angles

a/Sin A = b/Sin B = c/Sin C

2. The cosine rule looks like the Pythagoras’s theorem in notation but has a subtraction extension that multiplies two times the product of the other two sides and the cosine of the angle facing the side we want to calculate

So let’s say we want to calculate the side a in a triangle of sides a, b , c and we have the angle facing the side A

That would be;

a^2 = b^2 + c^2 -2bcCosA

So yes, the cosine rule can be used for the scenario above

3 0
3 years ago
A metal specimen with an original diameter of 0.50 in. and a gauge length of 2.75 in. is tested in tension until a fracture occu
tatiyna

Answer:

Percent Elongation = 52.72%

Percent Reduction in Area = 64%

Explanation:

First we find percent elongation:

Percent Elongation = {Final Gage Length - Initial Gauge Length/Initial Guage Length} x 100%

Percent Elongation = {(4.20 in - 2.75 in)/2.75 in} x 100%

<u>Percent Elongation = 52.72%</u>

Now, for the percent reduction in area:

Percent Reduction in Area = {Final Cross Sectional Area - Initial Cross Sectional Area|/Initial Cross Sectional Area Length} x 100%

Percent Reduction in Area = {π(0.3 in)² - π(0.5 in)²/π(0.5 in)²} x 100%

<u>Percent Reduction in Area = - 64%</u>

here, negative sign shows a decrease in area.

5 0
3 years ago
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