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3 years ago

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a spring of original length 10 cm, Stretches to 12 cm, when a Force of 40 N is applied to It. what is the extension of the sprin

g when a Force of 26 N, is applied?

1 answer:

Mila [183]3 years ago

8 0

Answer:

2.6

Explanation:

Since the formula is k=F/X when you criscross it becomes KX=F,10X=26,then over ten which equals 2.6.

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Need a little help here :(

Goshia [24]

Answer:

The output out be 200

Explanation:

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3 years ago

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What gas law looks at the relationship between pressure and temperature of a gas? A) Boyle's Law B) Charles' Law C) Gay Lussac's

Mandarinka [93]

Answer: it should be Boyle’s law

Explanation:

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3 years ago

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A piece of styrofoam has a charge of 0.002 mC and is placed 0.5 m from a grain of salt with a charge of 0.03 nC. How much electr

aleksklad [387]

Answer:

2.16×10⁻⁶ N

Explanation:

Applying,

F = kqq'/r² (coulomb's Law)....................... Equation 1

Where F = electrostatic force, k = coulomb's constant, q = charge on the styrofoam, q' = charge on the grain of salt, r = distance between the charges.

From the question,

Given: q = 0.002 mC = 2.0×10⁻⁶ C, q' = 0.03 nC = 3.0×10⁻¹¹ C, r = 0.5 m

Constant: k = 8.99×10⁹ Nm²/C²

Substitute these values into equation 1

F = (2.0×10⁻⁶)(3.0×10⁻¹¹)(8.99×10⁹)/0.5²

F = 2.16×10⁻⁶ N

5 0

3 years ago

Is 250 000 miles from the earth to the moon" is a qualitative<br> Observation<br> TRUE<br> Or false

lys-0071 [83]

Answer:

True

Explanation:

3 0

3 years ago

What is the average de Broglie wavelength of oxygen molecules in air at a temperature of 27°C? Use the results of the kinetic th

asambeis [7]

Answer:

$\lambda = 2.57 \times 10^{-11} m$

Explanation:

Average velocity of oxygen molecule at given temperature is

$v_{rms} = \sqrt{\frac{3RT}{M}}$

now we have

M = 32 g/mol = 0.032 kg/mol

T = 27 degree C = 300 K

now we have

$v_{rms} = \sqrt{\frac{3(8.31)(300)}{0.032}$

$v_{rms} = 483.4 m/s$

now for de Broglie wavelength we know that

$\lambda = \frac{h}{mv}$

$\lambda = \frac{6.6 \times 10^{-34}}{(5.31\times 10^{-26})(483.4)}$

$\lambda = 2.57 \times 10^{-11} m$

7 0

3 years ago