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Elena L [17]
2 years ago
10

Assuming that the acceleration of an object due to gravity is ag = 10 m/s2, it is possible to find the distance an object falls

when dropped by using the equation ay = \frac{1}{2} ag t2. Using this value for gravity, how far would an object drop after 5.0 s?
105 m
125 m
135 m
115 m
Physics
1 answer:
qwelly [4]2 years ago
7 0

Answer:

125 m

Explanation:

i just did the edpuzzle

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What time of the day do you feel the most Energetic and what do you usually do in those moments?​
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4 0
3 years ago
Read 2 more answers
Two forces are applied on a body. One produces a force of 480-N directly forward while the other gives a 513-N force at 32.4-deg
n200080 [17]

Answer:

F = (913.14 , 274.87 )

|F| = 953.61 direction 16.71°

Explanation:

To calculate the resultant force you take into account both x and y component of the implied forces:

\Sigma F_x=480N+513Ncos(32.4\°)=913.14N\\\\\Sigma F_y=513sin(32.4\°)=274.87N

Thus, the net force over the body is:

F=(913.14N)\hat{i}+(274.87N)\hat{j}

Next, you calculate the magnitude of the force:

F=\sqrt{(913.14N)+(274.87N)^2}=953.61N

and the direction is:

\theta=tan^{-1}(\frac{274.14N}{913.14N})=16.71\°

7 0
3 years ago
Which is the appropriate unit of measurement for pitch?
malfutka [58]
Hertz Pitch and frequency
6 0
2 years ago
Why do you rotate when you hold a spinning wheel?
choli [55]
When you hold a spinning wheel, the wheel and you, chair included, form a system that obeys the principle of "conservation of angular momentum". This means that any changes in angular momentum within the system must accompanied by an equal and opposite change, so the net force is zero.
4 0
3 years ago
NASA scientists suggest using rotating cylindrical spacecraft to replicate gravity while in a weightless environment. Consider s
dusya [7]

Answer:

Explanation:

Given

diameter of spacecraft d=148\ m

radius r=74\ m

Force of gravity F_g=mg

where m =mass of object

g=acceleration due to  gravity on earth

Suppose v is the speed at which spacecraft is rotating so a net centripetal  acceleration is acting on spacecraft which is given by

F_c=\frac{mv^2}{r}

F_c=F_g

\frac{mv^2}{r}=mg

\frac{v^2}{r}=g

v=\sqrt{gr}

v=\sqrt{1450.4}

v=38.08\ m/s    

8 0
3 years ago
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