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3 years ago

Unlike an acid, an aqueous solution of a base

Chemistry

1 answer:

HACTEHA [7]3 years ago

3 0

Answer:

D) contains more OH– ions than H+ ions

Explanation:

THESE ARE THE OPTIONS FOR THE QUESTION

A) causes some indicators to change color B) conducts electricity C) contains more H+ ions than OH– ions D) contains more OH– ions than H+ ions

Base can be regarded as substance which can dissociates in water then form hydroxide ions (OH–) .

Bases can be regarded as compounds which break into hydroxide ions I.e (OH-) with more other compounds if put in an aqueous solution. Hence it contains more OH– ions

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Calculate the experimental specific heat capacity of an object of mass 1.32 kg, given that the object releases 1.95 kJ of heat w

andreev551 [17]

Answer:

0.076 J/gºC.

Explanation:

From the question given above, the following data were obtained:

Mass (M) of object = 1.32 kg

Heat (Q) released = –1.95 kJ

Change in temperature (ΔT) = –19.5°C (decrease in temperature)

Specific heat capacity (C) =?

Next, we shall convert 1.32 kg to grams (g). This can be obtained as follow:

1 kg = 1000 g

Therefore,

1.32 kg = 1.32 kg × 1000 g / 1 kg

1.32 kg = 1320 g

Next, we shall convert –1.95 kJ to joule (J). This can be obtained as follow:

1 kJ = 1000 J

Therefore,

–1.95 kJ = –1.95 kJ × 1000 / 1 kJ

–1.95 kJ = –1950 J

Finally, we shall determine the specific heat capacity of the object. This can be obtained as follow:

Mass (M) of object = 1320 g

Heat (Q) released = –1950 J

Change in temperature (ΔT) = –19.5°C (decrease in temperature)

Specific heat capacity (C) =?

Q = MCΔT

–1950 = 1320 × C × –19.5

–1950 = –25740 × C

Divide both side by –25740

C = –1950 / –25740

C = 0.076 J/gºC

Thus, the specific heat capacity of the object is 0.076 J/gºC.

4 0

3 years ago

How many molecules of NH3 are in 45 mol of NH3 ?

crimeas [40]

Answer:

Explanation:

5 0

3 years ago

What is the Dependent variable?

horsena [70]

Explanation:

Just like an independent variable, a dependent variable is exactly what it sounds like. It is something that depends on other factors. For example, a test score could be a dependent variable because it could change depending on several factors such as how much you studied, how much sleep you got the night before you took the test, or even how hungry you were when you took it. Usually when you are looking for a relationship between two things you are trying to find out what makes the dependent variable change the way it does.

7 0

3 years ago

What happens when the dynamic equilibrium state of a system is disturbed by changing the conditions?

Lostsunrise [7]

Answer:

It covers changes to the position of equilibrium if you change concentration, pressure or temperature. ... If a dynamic equilibrium is disturbed by changing the conditions, the position of equilibrium moves to counteract the change

Explanation:

5 0

3 years ago

A horizontal pipe 15 cm in diameter and 4 m long is buried in the earth at a depth of 20 cm. The pipe-wall temperature is 75 deg

Basile [38]

Explanation:

The given data for case (1) is as follows.

h = 20 cm = 0.2 m

Assuming that a rectangular slab is placed above the pipe and we will calculate the heat transfer as follows.

Q = $kA \frac{\Delta T}{L}$

where, A = area

L = length

k = thermal conductivity = 0.8 W/m

$\Delta T$ = change in temperature.

Therefore, putting the given values into the above formula as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{0.2}$

= 168 W

For case (2), h = 180 cm = 1.8 m

Therefore, heat lost will be calculated as follows.

Q = $kA \frac{\Delta T}{L}$

= $0.8 W/m \times (4 m \times 0.15 m) \frac{75 - 5}{1.8}$

= 18.67 W

Thus, we can conclude that 18.67 W heat lost if the pipe was buried at a depth of 180 cm.

8 0

3 years ago