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lorasvet [3.4K]
3 years ago
10

What is Marie's velocity in section c 0.86mi/min 5mi/min 0mi/mi -5mi/min

Physics
1 answer:
Sergio [31]3 years ago
4 0

Answer:

0.5mi/min

Explanation:

Velocity = change in distance/time taken

Velocity= (5-0)/(20-10)=5/10=0.5mi/min

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A 10 N force is applied to a 2 kg mass, how fast will it be going in 10 seconds
prisoha [69]
Since
Force (weight) = mass x acceleration (gravity)

To determine acceleration, the formula will be:
Acceleration = Force / mass

Given are:
F = 10 N
M = 2kg
A = ?

Solution:

1. A = F/M
2. A = 10 kg*m/s2 / 2kg
3. A = 5 m/s2
5 0
4 years ago
An accelerating voltage of 2.47 x 10^3 V is applied to an electron gun, producing a beam of electrons originally traveling horiz
Dmitry [639]

Answer:

6.3445×10⁻¹⁶ m

Explanation:

E = Accelerating voltage = 2.47×10³ V

m = Mass of electron

Distance electron travels = 33.5 cm = 0.335 cm

E=\frac{mv^2}{2}\\\Rightarrow v=\sqrt{\frac{2E}{m}}\\\Rightarrow v=\sqrt{\frac{2\times 2470\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}}\\\Rightarrow v=29455356.08671\ m/s

Deflection by Earth's Gravity

\Delta =\frac {gt^2}{2}

Now, Time = Distance/Velocity

\Delta =\frac {g\frac{s^2}{v^2}}{2}\\\Rightarrow \Delta =\frac{9.81\frac{0.335^2}{29455356.08671^2}}{2}\\\Rightarrow \Delta =6.3445\times 10^{-16}\ m

∴ Magnitude of the deflection on the screen caused by the Earth's gravitational field is 6.3445×10⁻¹⁶ m

3 0
3 years ago
A poodle racing across a lawn is an example of _____.
sergey [27]


it is an example of kinetic energy

so the answer is b kinetic energy

6 0
3 years ago
A sprinter in a 100-m race accelerates uniformly for the first 71 m and then runs with constant velocity. The sprinter’s time fo
adoni [48]

Answer:

The acceleration of the sprinter is 1.4 m/s²

Explanation:

Hi there!

The equation of position of the sprinter is the following:

x = x0 + v0 · t + 1/2 · a · t²

Where:

x = position of the sprinter at a time t.

x0 = initial position.

v0 = initial velocity.

t = time.

a = acceleration.

Since the origin of the frame of reference is located at the starting point and the sprinter starts from rest, then, x0 and v0 are equal to zero:

x = 1/2 · a · t²

At t = 9.9 s, x = 71 m

71 m = 1/2 · a · (9.9 s)²

2 · 71 m / (9.9 s)² = a

a = 1.4 m/s²

The acceleration of the sprinter is 1.4 m/s²

3 0
4 years ago
How long will it take for a car to travel 200 km if it has an average speed of 55 km/hr? ​
andreyandreev [35.5K]

Answer: Approximately 3.65 hours

Explanation:

55 km/h x 3.65 hrs = 200.75 Km/h

4 0
3 years ago
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