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AysviL [449]
3 years ago
5

%7B%5Ccolorbox%7Bpurple%7D%7B%5Ccolorbox%7Bpink%7D%7B%5Ccolorbox%7Bgreen%7D%7B%5Ccolorbox%7Bgold%7D%7B%5Ccolorbox%7Bsilver%7D%7B%5Ctextit%7B%5Cpurple%7B%5Cunderline%7B%5Cgreen%7B%E3%80%8A%E2%9D%80question%E2%9C%BF%E3%80%8B%E0%BF%90%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D%7D" id="TexFormula1" title="\red{\underbrace{\overbrace\mathbb{\colorbox{aqua}{\colorbox{blue}{\colorbox{purple}{\colorbox{pink}{\colorbox{green}{\colorbox{gold}{\colorbox{silver}{\textit{\purple{\underline{\green{《❀question✿》࿐}}}}}}}}}}}}}}" alt="\red{\underbrace{\overbrace\mathbb{\colorbox{aqua}{\colorbox{blue}{\colorbox{purple}{\colorbox{pink}{\colorbox{green}{\colorbox{gold}{\colorbox{silver}{\textit{\purple{\underline{\green{《❀question✿》࿐}}}}}}}}}}}}}}" align="absmiddle" class="latex-formula">
Write \: the \: Physical  \:  Properties \: of \:  \\ SulphuricAcid
​
Chemistry
1 answer:
aleksandrvk [35]3 years ago
6 0

Answer:

<h2>Physical properties: H2SO4 is a colorless or slightly yellow viscous liquid with a pungent odor. It has a density of 1.84 g/mL, boiling point of 337 °C, and melting point of 10 °C. "Concentrated" sulfuric acid is 98% in water, and is the most stable form.</h2>
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Identify the property of the matter described below.
ZanzabumX [31]

Answer: C.

Explanation: Alcohol floats on oil and water sinks in oil. Water, alcohol, and oil layer well because of their densities, but also because the oil layer does not dissolve in either liquid. The oil keeps the water and alcohol separated so that they do not dissolve in one another. ... Water sinks because it is more dense than oil.

7 0
3 years ago
If the solvent is a liquid, then the solute:
Lelechka [254]

Answer:

must be either a gas or liquid

8 0
3 years ago
(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

7 0
3 years ago
A 50.0 mL sample of an aqueous H2SO4 solution is titrated with a 0.375 M NaOH solution. The equivalence point is reached with 62
vesna_86 [32]

Answer: The concentration of H_2SO_4 is 0.234 M

Explanation:

According to the neutralization law,

n_1M_1V_1=n_2M_2V_2

where,

n_1 = basicity H_2SO_4 = 2

M_1 = molarity of H_2SO_4 solution = ?

V_1 = volume of  H_2SO_4 solution = 50.0 ml

n_2 = acidity of NaOH = 1

M_1 = molarity of NaOH solution = 0.375 M

V_1 = volume of  NaOH solution = 62.5 ml

Putting in the values we get:

2\times M_1\times 50.0=1\times 0.375\times 62.5

M_1=0.234M

Therefore concentration of H_2SO_4 is 0.234 M

6 0
3 years ago
PROMISE I WILL MARK BRAINIEST NOT MUCH TIME
Galina-37 [17]
Your answer would be c 



hope this helps
4 0
3 years ago
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