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egoroff_w [7]
2 years ago
11

Calculate the power required for heating a 1.5 kg sample of water for 10 minutes in a thermal system. What is the amount of ener

gy required to raise the temperature of the water from 25°C to 60°C ? How much minimum amount of power does the heater have to supply per unit time? Why does the actual power rating of the heater need to be higher than this minimum amount? (The specific heat of water is 4.18 J/g°C .)
*60 points to anyone who can help*
Engineering
1 answer:
Masja [62]2 years ago
5 0

Answer:

Power= Heat energy\ time

heat energy= mc∆T

specific heat of water = 4180

1.5*4180*(60-25)

=219450

time = 10× 60= 600 secs

power = 219450/600

Power= 365.75 Watt

=0.37 KW

Explanation:

the actual has to be bigger because the heater might be required to handle more ...also to accommodate extra energy.

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Answer:

P_2-P_1=27209h

Explanation:

For pressure gage we can determine this by saying:

The closed tank with oil and air has a pressure of P₁ and the pressure of oil at a certain height in the U-tube on mercury is p₁gh₁. The pressure of mercury on the air in pressure gauge is p₂gh₂. The pressure of the gage is P₂.

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