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3 years ago

Someone please please help with this! I will mark brainliest if correct!!

Engineering

2 answers:

Advocard [28]3 years ago

8 0

E=I x R E = voltage, I = amps, R = resistance

12 = I x 12

I=1 is the correct answer is the correct answer to the question

jekas [21]3 years ago

5 0

resistor in series add so the total resistance is 12 ohms

E=I x R E = voltage, I = amps, R = resistance

12 = I x 12

I=1 is the answer to the question

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Answer:

The lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.

Explanation:

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A is given as

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With initial grade, the elevation of PVC is

$E_{PVC}=E_{PVI}+G_1(L/2)\\E_{PVC}=122+1.5%(460/2)\\E_{PVC}=125.45 ft\\$

The station is given as

$St_{PVC}=St_{PVI}-(L/2)\\St_{PVC}=24000-(230)\\St_{PVC}=237+70\\$

Low point is given as

$x=K \times |G_1|\\x=115 \times 1.5\\x=172.5 ft$

The station of low point is given as

$St_{low}=St_{PVC}-(x)\\St_{low}=23770+(172.5)\\St_{low}=239+42.5 ft\\$

The elevation is given as

$E_{low}=\frac{G_2-G_1}{2L} x^2+G_1x+E_{PVC}\\E_{low}=\frac{2.5-(-1.5)}{2*460} (1.72)^2+(-1.5)*(1.72)+125.45\\E_{low}=124.16 ft$

So the lowest point of the curve is at 239+42.5 ft where elevation is 124.16 ft.

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Answer:

Answered

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