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3 years ago

Which of these is a carbohydrate? O C6H1206 O C6H6012 C6H1302N C3H7O2NS

Chemistry

2 answers:

Xelga [282]3 years ago

7 0

Answer:

Explanation:

This is glucose. Glucose is a type of sugar, and because sugars are type of carbohydrate, glucose is a carbohydrate.

amm18123 years ago

4 0

Answer: The answer is the second choice.

Explanation:

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worty [1.4K]

C is the answer.
The temperature T in degrees Celsius (°C) is equal to the temperature T in Kelvin (K) minus 273°.

6 0

3 years ago

Read 2 more answers

Isobutyl propionate is the substance that provides the flavor for rum extract. combustion of a 1.152 g sample of this carbon-hyd

Ulleksa [173]

Answer;

C7H14O2

Solution;

Isobutyl contains , oxygen, carbon and hydrogen (total mass is 1.152 g)

Mass of carbon = 12/44 × 2.726 g

= 0.743455 g

Mass of Hydrogen = 2/18 × 1.116 g

= 0.124 g

Mass of oxygen = 1.152 - (0.7435 + 0.124)

= 0.2845 g

Moles of carbon ; 0.7435/12 = 0.06196 moles

Moles of hydrogen; 0.124/1 = 0.124 moles

Moles of oxygen; 0.2845/16 = 0.01778 moles

Ratios ; 0.06196/0.01778 ; 0.124/0.01778 : 0.01778/0.01778

= 3.5 : 7.0 : 1

To make them whole numbers ; we multiply the ratios by 2 to get;

(3.5 : 7.0 : 1 )2 = 7 : 14 : 2

Thus, the empirical formula of Isobutyl propionate is C7H14O2

4 0

3 years ago

Which of the following correctly describes the law of conservation of energy

egoroff_w [7]

Mass and energy can not be created or destroyed, they may be able to just be converted, and neither one seems without the opposite. For this reason in closed systems, both mass and energy are conserved individually. " I hope this helps "

3 0

3 years ago

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

Leokris [45]

Answer:

Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:

element & mass %

phosphorus & 39.18%

sulfur & 60.82%

Write the molecular formula of X.

Explanation:

The given molecule of phosphorus and sulfur has molar mass --- 316.25 g.

Empirical formula calculation:

element: phosphorus sulfur

co9mposition: 39.185% 60.82%

divide with

atomic mass: 39.185/31.0 g/mol 60.82/32.0g/mol

=1.26mol 1.90mol

smallest mole ratio: 1.26mol/1.26mol =1 1.90mol/1.26 mol =1.50

multiply with 2: 2 3

Hence, the empirical formula is:

P2S3.

Mass of empirical formula is:

158.0g/mol

Given, molecule has molar mass --- 316.25 g/mol

Hence, the ratio is:

316.25g/mol/158.0 =2

Hence, the molecular formula of the compound is :

2 x (P2S3)

= $P_4S_6$

8 0

2 years ago

You can practice converting between the mass of a solution and mass of solute when the mass percent concentration of a solution

LUCKY_DIMON [66]

Answer: The mass of solution having 768 mg of KCN is 426.66 grams.

Explanation:

We are given:

0.180 mass % of KCN solution.

0.180 %(m/m) KCN solution means that 0.180 grams of KCN is present in 100 gram of solution.

To calculate the mass of solution having 768 mg of KCN or 0.786 g of KCN (Conversion factor: 1 g = 1000 mg)

Using unitary method:

If 0.180 grams of KCN is present in 100 g of solution.

So, 0.768 grams of KCN will be present in = $\frac{100g}{0.180g}\times 0.768=426.66g$ of solution.

Hence, the mass of solution having 768 mg of KCN is 426.66 grams.

8 0

3 years ago