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Virty [35]
2 years ago
8

Brooke decides to model a lunar eclipse. She attaches a large poster of the Sun to her wall to represent the Sun. She then decid

es that her head will represent Earth, and the direction she is facing will indicate the direction an observer on Earth is facing. She will then hold a small ball in her hand to represent the Moon. In order to model a person watching a lunar eclipse, Brooke faces the "Sun," stretches out her hand, and faces the "Moon" in front of her. What aspect of Brooke's model should be corrected?
A. Brooke should turn so that the Sun is on her right, and hold the Moon to her left.
B. Brooke should turn so that her back is to the Sun, and hold the Moon behind her.
C. Brooke should turn so that the Sun is on her left, and hold the Moon in front of her.
D. Brooke should turn so that her back is to the Sun, and hold the Moon in front of her.
PLEASE HELP ITS A TEST :(((
Chemistry
1 answer:
koban [17]2 years ago
7 0

Answer:

its D

Explanation:

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When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
3 years ago
Can light bend around corners to reach an object
Sholpan [36]

Answer: Yes, light can bend around corners. In fact, light always bends around corners to some extent.

Explanation:This is a basic property of light and all other waves. ... The ability of light to bend around corners is also known as "diffraction".

7 0
3 years ago
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Given the following information: benzoic acid = C6H5COOH hydrocyanic acid = HCN C6H5COOH is a stronger acid than HCN (1) Write t
Maurinko [17]

Answer:

The net ionic equation is

C6H5COOH+ CN-= C6H5COO- + HCN

Explanation:

From the ionic equation

C6H5COOH + Na+ + CN- = C6H5COO- + Na+ + HCN

Only sodium is the spectator ion, so it cancels out, since C6H5COOH and HCN do not ionize completely they are left undissociated

5 0
3 years ago
Calculate the density of chloroform
Rina8888 [55]

Answer: The density of chloroform is 1.47 g/mL

Explanation : Given,

Volume = 40.5 mL

Mass of cylinder = 85.16 g

Mass of cylinder and liquid = 145.10 g

First we have to calculate the mass of liquid (chloroform).

Mass of liquid = Mass of cylinder and liquid - Mass of cylinder

Mass of liquid = 145.10 g - 85.6 g

Mass of liquid = 59.5 g

Now we have to calculate the density of liquid (chloroform).

Formula used:

Density=\frac{Mass}{Volume}

Now putting g all the given values in this formula, we get:

Density=\frac{59.5g}{40.5mL}

Density=1.47g/mL

Therefore, the density of chloroform is 1.47 g/mL

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When an ionic compound dissolves in water: When an ionic compound dissolves in water: the solvent-solute attractive forces overc
oksano4ka [1.4K]

Answer:

each of the above (A, B, and C) occurs

Explanation:

When an ionic compound dissolves in the water, the following happens :

-- the solvent solute attractive forces tries to overcome the solute solute attractions.

-- the water dipoles' negative end attracts the positive ions

--  the water dipoles' positive end attracts the negative ions

For example,

NaCl which is an ionic compound and also a strong electrolyte, it dissociates into water on the hydrated Na cations as well as Cl anions.

In water, the oxygen has negative charge and thus attracts the positive ions of the sodium, whereas the hydrogen is of positive and it attract the ions of chlorine which is negative.

8 0
3 years ago
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