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liberstina [14]
3 years ago
12

A baseball (m = 140 g) traveling at 30. m/s moves a fielder's glove backward 35 cm when the ball is caught.  

Physics
1 answer:
koban [17]3 years ago
5 0

Answer:

180

Explanation:

1) E=F*L, where E - energy of the baseball, F - the required force, L - backward moving (0.35m);

2) E=mV²/2, where E - energy of the baseball, m - the mass of the baseball (0.14kg), V - the velocity of the baseball (30m/s).

3) if E=F*L and E=mV²/2, then F*L=mV²/2, from which

F=\frac{mV^2}{2L};

4) according to the last formula

F=\frac{0.14*900}{2*0.35}=\frac{126}{0.7}=180(N).

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Answer:

241.8 N.

Explanation:

The force on branch provides a reaction to the ape's weight force plus the centripetal force needed to keep the gibbon in a circular motion of radius 0.60 m.

Centripetal force = mv^2/r

F = mg + mv²/r

F = m(g + v²/r)

where,

m = mass

= 9 kg

g = acceleration due to gravity

= 9.8 m/s²

v = 3.2 m/s

r = 0.60 m

F = 9 * (9.8 + 3.2²/0.60)

= 241.8 N.

3 0
3 years ago
A 10kg oil is heated by a source of heat that supplies 800J of heat every minute. Calculate The heat added to oil after 30 minut
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Answer:

4,200 joules per kilogram per degree Celsius

Explanation:

The specific heat capacity of a material is the energy required to raise one kilogram (kg) of the material by one degree Celsius (°C). The specific heat capacity of water is 4,200 joules per kilogram per degree Celsius (J/kg°C). This means that it takes 4,200 J to raise the temperature of 1 kg of water by 1°C.

4 0
2 years ago
An electron experiences a downward force of 12.8×10-19 N while traveling in a magnetic field of 8×10-5 T west, what is the magni
SashulF [63]

Answer:

v=10^5\ m/s

Explanation:

Given that,

Magnetic force acting on an electron, F=12.8\times 10^{-19}\ N

The magnitude of the magnetic field,B=8\times 10^{-5}\ T

We need to find the magnitude of the velocity. We know that the magnetic force is given by :

F=qvB

Where

v is the velocity

So,

v=\dfrac{F}{qB}\\\\v=\dfrac{12.8\times 10^{-19}}{1.6\times 10^{-19}\times 8\times 10^{-5}}\\\\v=10^5\ m/s

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3 years ago
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Varvara68 [4.7K]

Answer:

0.0018833\ \text{m/s}

Explanation:

d = Distance of Andromeda Galaxy from Earth = 2.54\times 10^7\ \text{ly}

t = Time taken = 90\ \text{years}

c = Speed of light = 3\times 10^8\ \text{m/s}

We have the relation

t=t_o\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow 90=2.54\times 10^7\sqrt{1-\dfrac{v^2}{c^2}}\\\Rightarrow \dfrac{90^2}{(2.54\times 10^7)^2}=1-\dfrac{v^2}{c^2}\\\Rightarrow 1-\dfrac{90^2}{(2.54\times 10^7)^2}=\dfrac{v^2}{c^2}\\\Rightarrow v=c\sqrt{1-\dfrac{90^2}{(2.54\times 10^7)^2}}

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The required answer is 0.0018833\ \text{m/s}.

7 0
3 years ago
How many turns are in the secondary coil of a step up transformer that increases voltage from 30 V to 150 V and has seven turns
Mademuasel [1]

350 + 507 = 3657 that would be your answer

7 0
3 years ago
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