Question

A certain force gives object m1 an acceleration of 12.0 m/s2. The same force gives object m2 an acceleration of 3.30 m/s2. What acceleration would the force give to an object whose mass is (a) the difference between m1 and m2 and (b) the sum ofm1 andm2

Answer 1

Answer:

a)   a = 4,552 m / s²,   b)  a = 2,588 m / s²

Explanation:

Newton's second law is

          F = ma

          a = F / m

in this case the force remains constant

indicate us

* for a mass m₁

       a₁ = F/m₁

       a₁ = 12, m/ s²

* for a mass m₂

        a₂= 3.3 m / s²

a) acceleration

       m = m₂-m₁

we substitute

        a = $\frac{F}{m_2 - m_1}$

        1 / a = $\frac{m_2}{F} - \frac{m_1}{F}$

let's calculate

        $\frac{1}{a}$ = $\frac{1}{3.3} - \frac{1}{12}$

         $\frac{1}{a}$ = 0.21969

         a = 4,552 m / s²

b)   m = m₂ + m₁

     a = F / (m₂ + m₁)

     $\frac{1}{a} = \frac{m_2}{F} + \frac{m_1}{F}$

we substitute

           $\frac{1}{a} = \frac{1}{3.3} + \frac{1}{12}$

           a = 2,588 m / s²