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Serga [27]
2 years ago
13

What electives should i take in highschool to prepare to take criminology?

Chemistry
1 answer:
dybincka [34]2 years ago
4 0

Answer:

depending on what school you go to and what classes you are allowed to take in which grades, you should take forensics.

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I am a mental with 28 electrons
musickatia [10]
I am a Nickel.
You're welcome.
3 0
3 years ago
Which one of the following does not represent 1.000 mol of the indicated
Katen [24]

Answer:

B. 26.00 g Fe

Atomic mass of Fe (Iron) is 55.845g

3 0
3 years ago
Read 2 more answers
If 500.0 mL of 0.10 M Ca2+ is mixed with 500.0 mL of 0.10 M SO42−, what mass of calcium sulfate will precipitate? Ksp for CaSO4
statuscvo [17]

Answer:

The mass of calcium sulfate that will precipitate is 6.14 grams

Explanation:

<u>Step 1:</u> Data given

500.0 mL of 0.10 M Ca^2+ is mixed with 500.0 mL of 0.10 M SO4^2−

Ksp for CaSO4 is 2.40*10^−5

<u>Step 2:</u> Calculate moles of Ca^2+

Moles of Ca^2+ = Molarity Ca^2+ * volume

Moles of Ca^2+ = 0.10 * 0.500 L

Moles Ca^2+ = 0.05 moles

<u>Step 3: </u>Calculate moles of SO4^2-

Moles of SO4^2- = 0.10 * 0.500 L

Moles SO4^2- = 0.05 moles

<u>Step 4: </u>Calculate total volume

500.0 mL + 500.0 mL = 1000 mL = 1L

<u>Step 5: </u> Calculate Q

Q = [Ca2+] [SO42-]  

[Ca2+]= 0.050 M   [O42-]

Qsp = (0.050)(0.050 )=0.0025 >> Ksp

This means precipitation will occur

<u> Step 6:</u> Calculate molar solubility

Ksp = 2.40 * 10^-5 = [Ca2+][SO42-] =(x)(x)

2.40 * 10^-5 = x²

x = √(2.40 * 10^-5)

x = 0.0049 M = Molar solubility

<u> Step 7:</u> Calculate total CaSO4 dissolved

total CaSO4 dissolved = 0.0049 M * 1 L * 136.14 mol/L = 0.667 g

<u>Step 8:</u> Calculate initial mass of CaSO4

Since initial moles CaSo4 = 0.050

Initial mass of CaSO4 = 0.050 * 136.14 g/mol

Initial mass of CaSO4 = 6.807 grams

<u>Step 9:</u> Calculate mass precipitate

6.807 - 0.667 = 6.14 grams

The mass of calcium sulfate that will precipitate is 6.14 grams

5 0
3 years ago
What is the initial temperature (°C) of a system that has the pressure decreased by 10 times while the volume increased by 5 tim
Ede4ka [16]

Answer:

300K

Explanation:

Given pressure of the system decreased by 10 times which means P_{2} =\frac{P_{1} }{10}

Given the volume of the system increased by 5 times which means V_{2} =5\times V_{1}

Given final temperature T_{2}=150K

Let the initial temperature be T_{1}

We know that PV=nRT

As n and R are constant \frac{PV}{T}=constant

\frac{P_{1}V_{1} }{T_{1}} =\frac{P_{2}V_{2}}{T_{2}}

T_{1} =\frac{P_1V_1}{P_2V_2} T_{2}

T_{1} =2\times T_{2}

T1=300K

8 0
3 years ago
For the following formula, C4H9Cl, calculate the IHD and select all the types of unsaturation that might be present in the molec
Airida [17]

Answer:

The IHD = 0

There is no unsaturation in the compound C4H9Cl

Explanation:

IHD = Index for Hydrogen Deficiency .It determines total number of unsaturation or Pi- bond present in the molecule.It is calculated using the formula:

For Molecule:

C_{c}H_{h}O_{o}N_{n}X_{x}

Here . C = carbon

H = Hydrogen

O = Oxygen

N = Nitrogen

X = Halogen

The IHD is calculated as :

\frac{2c-h-x+n+2}{2}...............(1)

For example :

C4H8O2

Here c = 4 , h = 8 , o = 2 .

n = x=0

Put the value in equation (1) and find IHD

\frac{2(4)-8-0+0+2}{2}

\frac{8-8+2}{2}

\frac{2}{2}

IHD = 1

For C4H9Cl

c = 4 , h = 9 and  x = 1

IHD for this molecule can be calculated as :

\frac{2c-h-x+n+2}{2}

\frac{2(4)-9-1+2}{2}

\frac{8-9-1+2}{2}

= 0

This means there is no unsaturation in the molecule.

Each bond is sigma bond and properly saturated.

5 0
3 years ago
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