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Nata [24]
3 years ago
13

Round off to the nearest one (units place):

Physics
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

(a) 57

(b) 9

(c) 291

(d) 1394

(e) 434

Elina [12.6K]3 years ago
7 0

Answer:

a

Explanation:

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What does it mean, if the specific gravity of an object is less than one?​
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Answer:

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2 years ago
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If you push on a wall with a force of 200 N, with what force does the wall push back?
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200 N, that is if the force is balanced and the wall doesn't move
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Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass
kirza4 [7]

Answer:

a. 0.342 kg-m² b. 2.0728 kg-m²

Explanation:

a. Since the skater is assumed to be a cylinder, the moment of inertia of a cylinder is I = 1/2MR² where M = mass of cylinder and r = radius of cylinder. Now, here, M = 56.5 kg and r = 0.11 m

I = 1/2MR²

= 1/2 × 56.5 kg × (0.11 m)²

= 0.342 kgm²

So the moment of inertia of the skater is

b. Let the moment of inertia of each arm be I'. So the moment of inertia of each arm relative to the axis through the center of mass is (since they are long rods)

I' = 1/12ml² + mh² where m = mass of arm = 0.05M, l = length of arm = 0.875 m and h = distance of center of mass of the arm from the center of mass of the cylindrical body = R/2 + l/2 = (R + l)/2 = (0.11 m + 0.875 m)/2 = 0.985 m/2 = 0.4925 m

I' = 1/12 × 0.05 × 56.5 kg × (0.875 m)² + 0.05 × 56.5 kg × (0.4925 m)²

= 0.1802 kg-m² + 0.6852 kg-m²

= 0.8654 kg-m²

The total moment of inertia from both arms is thus I'' = 2I' = 1.7308 kg-m².

So, the moment of inertia of the skater with the arms extended is thus I₀ = I + I'' = 0.342 kg-m² + 1.7308 kg-m² = 2.0728 kg-m²

5 0
3 years ago
w = wavelength Temperature = 23C w = 4 (L + 0.4 D) L = length of pipe v = f w D = diameter = 3 cm v = 331 + 0.6 T A variety of t
Effectus [21]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

8 0
4 years ago
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