Answer: The observed frequency is 518.6 Hz
Explanation:
By the Doppler Effect, we know that:
f' = ((v + v0)/(v - vs))*f
where f' is the perceived frequency.
v is the velocity of the wave, in this case 330m/s
v0 is the velocity of the receptor, in this case 0m/s
vs is the velocity of the source, in this case -50m/s (the minus sign is because it is coming thowards us)
f is the original frequency, f = 440hz.
then we have:
f' = 440hz*(330m/s)/(330m/s - 50m/s) = 518.6 Hz
There is a huge diffrenc like one is following christ the other is bringing the devil to pepole
Using V²=u² +2gH
let's assume the ball falls from rest, then it's initial velocity = 0ms-¹ (U=0)
then from the above info V= 35ms-¹
g= 10ms-² (value of acceleration due to gravity to the nearest tens)
so input your values above into the given formula to find height
35² = 0² +2×10×H
1225 = 20H
H = 1225÷20 = 61.25m
Answer:
They preserve many good_from historyof nepal_for us(from history of nepal)
