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IrinaK [193]
3 years ago
5

When the notebook is sitting on the table, what force prevents it from falling into the space below the table? If you don’t know

the name of this force, just describe it. What force keeps the notebook from floating in the air?
Physics
1 answer:
Xelga [282]3 years ago
4 0

Answer:

reaction force/normal force (its when the tables kinda pushing from under so it doesnt fall)

and the notebook wont float bc of gravity

Explanation:

theres a quizlet on this if you wanna check it out lol

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Suppose a distant world with surface gravity of 5.20 m/s2 has an atmospheric pressure of 7.16 ✕ 104 Pa at the surface. (a) What
Nesterboy [21]

Answer:

899752.13598 N

Explanation:

p = Pressure on the plate = 7.16\times 10^4\ Pa

A = Area = \pi r^2=\pi 2^2=\pi 4

F = Force on the region

When force is divided by area we get pressure

p=\frac{F}{A}\\\Rightarrow F=p\times A\\\Rightarrow F=7.16\times 10^4\times \pi 4\\\Rightarrow F=899752.13598\ N

Force is exerted by the atmosphere on a disk-shaped region is 899752.13598 N

6 0
3 years ago
wide tube that extends down from the bag of solution, which hangs from a pole so that the fluid level is 90.0 cm above the needl
Bingel [31]

Answer:

The average gauge pressure inside the vein is 110270.58 Pa

Explanation:

This question can be solved using the Bernoulli's Equation. First, in order to determine the outlet pressure of the needle, we need to find the total pressure exerted by the atmosphere and the fluid.

P_f: fluid's\ pressure\\P_f= \rho g h=1025\frac{kg}{m^3} \times 9.8 \frac{m}{s^2} \times 0.9 m=9040.5 Pa \\P_T: total\ pressure\\P_T=P_{atm}+P_f\\P_T=101325 Pa + 9040.5 Pa=110275.5 Pa\\

Then, we have to find the fluid's outlet velocity with the transversal area of the needle, as follows:

S: transversal\ area \\S= \pi r^2=\pi (0.200 \times 10^{-3})^2=5.65 \times 10^{-7} m^2\\v=\frac{F}{S}=\frac{5.55 \times 10^{-8} \frac{m^3}{s}}{5.65 \times 10^{-7} m^2}=0.98\times 10^{-1} \frac{m}{s}

As we have all the information, we can complete the Bernoulli's expression and solve to find the outlet pressure as follows:

P_T-P_{out}=\frac{1}{2} \rho v^2\\P_{out}=P_T-\frac{1}{2} \rho v^2=110275.5 Pa-\frac{1}{2} 1025\frac{kg}{m^3} (0.98\times 10^{-1} \frac{m}{s})^2=110275.5 Pa-4.92 Pa =110270.58 Pa

6 0
3 years ago
El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
topjm [15]

Answer:

P₁ = 219.3 Pa

Explanation:

This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.

Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.

              P₁ = P₂

pressure is defined by

             P = F / A

we subtitute

             F₁ / A₁ = F₂ / A₂

             F₁ = F₂ A₁ / A₂

the area in a circle is

             A = π r² = π d² / 4

we substitute

            F₁ = F₂ (d₁ / d₂)²

we calculate

           F₁ = 17640 (2/32)²

           F₁ = 68.9 N

Having the force to be applied we can find the air pressure on the small plunger

          P₁ = F₁ / A₁

          P₁ = F₁ 4 / π d₁²

let's calculate

          P₁ = 68.9 4 / (π 0.02²)

          P₁ = 219.3 Pa

3 0
3 years ago
how many days does it take a team of drivers to drive a truck california and back to lansing if the drivers average 15m/s includ
malfutka [58]

4days and 12hours

Explanation:

Given parameters:

Average speed  = 15m/s

Distance = 1800 miles

Unknown:

Number of days = ?

Solution:

Speed is the rate of change of distance with time;

          Speed = \frac{distance}{time}

Since the unknown is number of days, it is a measure of time:

    Time = \frac{distance }{speed}

The distance from California to Lansing is 1800miles. The journey takes the truck drivers to and fro. It is a two way trip;

 Total distance = 1800 miles x 2 = 3600miles

We need to convert miles to meters since that is the unit we can conveniently work with;

            1 mile = 1609.34m

          3600 miles =  3600 x 1609.34

                              = 5793638m

Inputting the values in the equation:

          Time = \frac{ 5793638}{15} = 386242.53s

Now we need to convert to day;

In a day, = 60 x 60 x 24 = 86,400s

                 1 day = 86400s

 Therefore;

  The number of days = \frac{386242.53}{86400} = 4.47days

This implies that it will take them 4 days and approximately 12 hours.

learn more:

speed brainly.com/question/10048445

#learnwithBrainly

7 0
3 years ago
A fire engine is rapidly approaching you at a stop light. What happens to the frequency and pitch of the sound as the fire engin
ValentinkaMS [17]

Answer:

The frequency increases, and the pitch increases

Explanation:

  • Doppler's law of sound is applicable in such case when the observer or the sound source or both are moving relative to each other.
  • In such a case due to space-time constraint the waveform of the sound adjust themselves so as to obey the law of conservation of energy.

<u>The apparent frequency of the sound for the observer is given by:</u>

f_o=(\frac{s+v_o}{s+v_s} )f ....................................(1)

where:

f_o= observed frequency

f= original source frequency

s= speed of sound

v_s= speed of source relative to the observer (taken negative when approaching towards the observer and vice-versa)

v_o= speed of observer relative to the source (taken negative when moving away from the source and vice-versa)

<u>According to the given situation, eq. (1) becomes:</u>

f_o=(\frac{s}{s-v_s} )f

Since, \frac{s}{s-v_s} >1

Therefore

f_o>f

Pitch is very closely related to the frequency, it means that how fast is the amplitude of sound varying with time.

7 0
3 years ago
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