Answer:
heat is not absorbed by the system
A rapid shift occurs between gas compression and expansion.
All heat is transformed to work done by the system.
Explanation:
Answer:
a) The shear stress is 0.012
b) The shear stress is 0.0082
c) The total friction drag is 0.329 lbf
Explanation:
Given by the problem:
Length y plate = 2 ft
Width y plate = 10 ft
p = density = 1.938 slug/ft³
v = kinematic viscosity = 1.217x10⁻⁵ft²/s
Absolute viscosity = 2.359x10⁻⁵lbfs/ft²
a) The Reynold number is equal to:
The boundary layer thickness is equal to:
ft
The shear stress is equal to:
b) If the railing edge is 2 ft, the Reynold number is:
The boundary layer is equal to:
The sear stress is equal to:
c) The drag coefficient is equal to:
The friction drag is equal to:
Answer:
50m/s, 187.5m
Explanation:
Consider unit analysis:
m/s² = m/(s×s)
This can be read as "meters per second, per second". From fundamental kinematics, meters per second is the same as saying velocity.
Velocity is being increased per second, and this is called acceleration:
a = v/t, where a is acceleration, v is change of velocity and t is change of time. "Change" is represented by a triangle called delta and (delta)A = A2 - A1
From the question, we have the variables:
a = 5m/s²
(delta)v = v2 - 25m/s
(delta)t = 5s (initial time is 0)
a = v/t
(5m/s^2)=v/5s
25m/s = v2 - 25m/s
50m/s = v2
The final velocity of the vehicle is 50m/s.
A formula exists to find displacement with regards to acceleration:
d=v(initial) × t +1/2 × a × t²
d=25m/s × 5s + 1/2 × 5m/s² ×(5s)²
d=125m+1/2×125m
d=125m+62.5m
d=187.5m
The distance travelled by the vehicle is 192.5m.
<em>One of the most important skills you can have in any science is unit analysis. Treat meters, seconds, moles, etc as </em><em>values</em><em> when doing </em><em>calculations</em><em> </em><em>and see if you get the result you're looking for.</em>
Answer:
In positive feedback mechanism, the output is fed back to the system which further increases the output. Hence, it is known as positive feedback because it amplifies the output.
In the negative feedback mechanism, the output is fed back to the system which further decreases the the output. Hence, it is known as negative feedback because it reduces the output.
<span> applies to any object moving more slowly than the speed of light</span>
