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Ugo [173]
3 years ago
10

A car driving at 25 m/s, travels 318 m. How long does it take?

Physics
1 answer:
labwork [276]3 years ago
7 0

Answer:

12.72 sec

Explanation:

The time it takes to travel a certain distance can be found by dividing the distance that needs to be travelled by the speed with which you are travelling, therefore...

Time = \frac{Distance}{Speed} = \frac{318}{25} = 12.72 sec

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11.9 minutes

Explanation:

The journey is 5000 meters long. The time it takes in seconds for the journey at this speed is 5000/7 =714 seconds.

714/60=time in minutes =11.9 minutes approximately.

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What is better for measuring how hard you are actually working, Target Heart Rate or Rating of perceived exertion?
emmainna [20.7K]

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Explanation:

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A 51.0 kg cheetah accelerates from rest to its top speed of 31.7 m/s. HINT (a) How much net work (in J) is required for the chee
andrey2020 [161]

(a) 2.56\cdot 10^4 J

The work-energy theorem states that the work done on the cheetah is equal to its change in kinetic energy:

W= \Delta K = \frac{1}{2}mv^2 - \frac{1}{2}mu^2

where

m = 51.0 kg is the mass of the cheetah

u = 0 is the initial speed of the cheetah (zero because it starts from rest)

u = 31.7 m/s is the final speed

Substituting, we find

W=\frac{1}{2}(51.0 kg)(31.7 m/s)^2 - \frac{1}{2}(51.0 kg)(0)^2=2.56\cdot 10^4 J

(b) 6.1 cal

The conversion between calories and Joules is

1 cal = 4186 J

Here the energy the cheetah needs is

E=2.56\cdot 10^4 J

Therefore we can set up a simple proportion

1 cal : 4186 J = x : 2.56\cdot 10^4 J

to find the equivalent energy in calories:

x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal

3 0
3 years ago
"Sarah is out playing fetch with her dog, and throws a tennis ball as far as she can. At the moment the ball reaches its maximum
e-lub [12.9K]

Answer:

<h2>a.The ball's vertical acceleration is downwards.</h2><h2>e.The ball's horizontal acceleration is zero</h2>

Explanation:

We are given that Sarah throws a tennis ball as far as she can.

At the moment the ball reaches its maximum height.

We have to find the true statement if air resistance is neglect.

When air resistance is negligible then the force act on the ball is force due to gravity.

The ball throw vertically then the acceleration act on the ball is acceleration due to gravity.

The value of g=-9.8 m/square sec

It acts on the ball in downward direction .

Therefore, the ball's vertical acceleration is downwards.

The horizontal acceleration is zero because the ball reaches at maximum height then there is no force which act in horizontal direction on the ball.

Therefore, horizontal acceleration of the ball is zero.

Hence, option a and e are true.

3 0
3 years ago
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