Caffeine has the following percent composition: carbon 49.48%, hydrogen 5.19%, oxygen 16.48% and nitrogen 28.85%. Its molecular weight is 194.19 g/mol.
Use PV =nRT
so P = nRT/V
= 1 mole(0.08205 L atm/K mol)(1000K) / 2 L
= 41 atm
The process of an atom releasing energy when it moves to a lower energy state is called emission.
Answer:
The molecular formula of glucose is C₆H₁₂O₆
Explanation:
Empirical formula:
It is the simplest formula gives the ratio of smallest whole number of atoms.
Molecular formula:
It gives the total number of atoms in a molecule of compound.
The molecular formula and empirical formula can be related as follow:
Molecular formula = n × empirical formula
Given data:
Empirical formula = CH₂O
Molecular formula = ?
It is stated in given problem that molecular formula is the 6 times of the empirical formula.
Molecular formula = n × empirical formula
Molecular formula = 6 × CH₂O
Molecular formula = C₆H₁₂O₆
The molecular formula of glucose is C₆H₁₂O₆.