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-Dominant- [34]
3 years ago
8

A balloon contains 7.36 g of oxygen gas (O2). How many oxygen molecules are in the balloon?

Chemistry
1 answer:
Firlakuza [10]3 years ago
7 0
Avagadros constant states that 1 mol of any substance is made of 6.022 x 10^23 units.
These units could be atoms making up elements or molecules making up compounds.
1 mol of molecular oxygen (O2) is made of 6.022 x 10^23 molecules of O2
The mass of 1 mol of O2 is 32 g/mol
This means that the number of oxygen molecules in 32 g are 6.022 x 10^23 molecules
Therefore in 7.36 g of oxygen gas there are - 6.022 x 10^23 /32 g/mol x 7.36 g = 1.39 x 10^23 oxygen molecules
Answer is 1.39 x 10^23 oxygen molecules
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3 years ago
A student mixes a solution containing 10.0 g bacl2 (m = 208.2) with a solution containing 10.0 g na2so4 (m = 142.1) and obtains
professor190 [17]
The balanced equation for the above reaction is as follows;
Na₂SO₄ + BaCl₂ --> BaSO₄ + 2NaCl
Na₂SO₄ reacts with BaCl₂ in the molar ratio 1:1
Number of Na₂SO₄ moles - 10.0 g / 142.1 g/mol = 0.0704 mol
Number of BaCl₂ moles - 10.0 g / 208.2 g/mol = 0.0480 mol
this means that 0.0480 mol of each reactant is used up, BaCl₂ is the limiting reactant and Na₂SO₄ has been provided in excess. 
stoichiometry of BaCl₂ to BaSO₄ is 1:1
number of BaSO₄ moles formed - 0.0480 mol
Mass of BaSO₄ - 0.0480 mol x 233.2 g/mol = 11.2 g
theoretical yield is 11.2 g but the actual yield is 12.0 g
the actual product maybe more than the theoretical yield of the product as the measured mass of the actual yield might contain impurities. 
percent yield - 12.0 g/ 11.2 g x 100% = 107% 
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4 0
3 years ago
A marble is L 1.32 W 1.32 H 1.32, what is the volume? Show your work
cupoosta [38]

The volume of the marble is 2.3 cube units.

From the question given above, the following data were obtained:

  • Length (L) = 1.32
  • Width (W) = 1.32
  • Height (H) = 1.32
  • Volume (V) =?

The volume of the marble can be obtained as follow:

V = L × W × H

V = 1.32 × 1.32 × 1.32

V = 2.3 cube units

Thus, the volume of the marble is 2.3 cube units.

Learn more about volume:

brainly.com/question/20665757

6 0
2 years ago
7) Which element would have the lowest first ionization energy? *<br> Li<br> Be<br> Na<br> Mg
olga_2 [115]

Answer:

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Explanation:

7 0
3 years ago
Read 2 more answers
A .115 L sample of dry air has a pressure of 1.0895633 atm at 377 K. What is the volume of the sample if the temperature is incr
matrenka [14]

Answer:

V= 0.147 L

Explanation:

This is simply the application of combined gas law twice, to find the unknowns.

Combined gas law states that: PV = nRT

P= pressure of air

V= volume of air

n= moles of air

R= Universal gas constant ( 0.08205 L atm mol⁻¹ K⁻¹)

T= Absolute temperature in kelvin.

n=\frac{P * 0.115}{R * 377}

Now, applying the same gas law at 483K and substituting for n

V = \frac{P * 0.115}{R * 377} * \frac{R* 483}{P}

V= \frac{0.115 * 483}{377}

V= 0.147 L

4 0
3 years ago
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