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uranmaximum [27]

3 years ago

11

A truck skids for a distance of 25m with the road pushing on its tires with force of 1500N as its brakes are applied. What is th

e change in kinetic energy for the truck?

1 answer:

Daniel [21]3 years ago

3 0

Answer:

37500 J

Explanation:

Law of conservation of energy: Its states that energy can neither be created nor destroyed but it can be transformed from one form to another.

Applying the law of conservation of energy.

The change in kinetic energy for the truck = Net work done by the truck skids

ΔK.E = F×d.................... Equation 1

Where ΔK.E = Change in kinetic energy, F = Force, d = distant.

Given: F = 1500 N, d = 25 m

Substitute these values into equation 1

ΔK.E = 1500×25

ΔK.E = 37500 J

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Describe briefly with used of practical knowledge the effect of the voltage stores across and current

DaniilM [7]

Answer:

Answer in explanation

Explanation:

The path of flow of circuit is called electric circuit. In an electric circuit, resistances are connected in two different ways, which are:

1- Series Combination of Resistances

2- Parallel Combination of Resistances

<u>Series combination of resistances </u>

In series combination resistors are connected end to end, and there is only one path for the flow of current.

Characteristics Of Series Circuit:

1. In series circuit there is only one path for the flow of current.

2. Same amount of current flows through each resistor.

I = I₁ = I₂ = I₃ = In

3. Total voltage of the battery is equal to the sum of voltages across each resistor.

V = V₁ +V₂ + V₃ + ... + Vn

4. In series combination the combined resistance of the resistors can be obtained by adding the value of each resistor.

R = R₁ + R₂ + R₃ + … + Rn

<u>Parallel combination of resistances </u>

Resistances are set to be connected in parallel, when each of them is connected directly from the terminals of electric source.

Characteristics Of Series Circuit:

1. There are more than one path for the flow of current.

2. The value of potential difference remains constant on each resistor.

V = V₁ = V₂ = V₃ = Vn

3. Total current is equal to the sum of current passing through each resistor.

I = I₁ + I₂ + I₃ +...+ In

4. Reciprocal of equivalent resistance is equal to the sum of reciprocals of resistances connected in parallel.

1/R = 1/R₁ + 1/R₂ + 1/R₃ + … + 1/Rn

The circuit diagrams are in attachment.

7 0

3 years ago

One runner in a relay race has a 1.50 s lead and is running at a constant speed of 3.25 m/s. The runner has 30.0 m to run before

yarga [219]

The second runner must run 3.3m/s. If the leading runner is 1.5 seconds ahead and there are 30m left, the second runner would need to run slightly faster than the lead in order to finish at the same time. To calculate this I did 30/1.5 which gave me 0.05. I added this onto the speed of the lead runner to get 3.3m/s :)

6 0

3 years ago

Read 2 more answers

28. Ken and Musa shared a cake such that Ken got twice the size

ratelena [41]

Answer:

$Musa = \frac{1}{3}$

$Ken = \frac{2}{3}$

Explanation:

Given

$Ken = 2 * Musa$ --- Ken's share

Required

The fraction each got

Since they both shared a cake, we have:

$Ken + Musa = 1$

Substitute: $Ken = 2 * Musa$

$2 * Musa+ Musa = 1$

Factorize

$Musa(2+ 1)= 1$

$Musa(3)= 1$

Divide both sides by 3

$Musa = \frac{1}{3}$

Recall that: $Ken = 2 * Musa$

$Ken = 2 * \frac{1}{3}$

$Ken = \frac{2}{3}$

3 0

3 years ago

A certain copper wire has a resistance of 13.0 Ω . At some point along its length the wire was cut so that the resistance of one

alekssr [168]

Answer with Explanation:

Let r be the resistance of short piece of copper wire.

Resistance of copper wire=R= $13\Omega$

Resistance is directly proportional to length.

If a wire has greater resistance then,the wire will be greater in length.

Therefore,resistance of long piece of wire=7r

Total resistance of copper wire=Sum of resistance of two piece of wires

$r+7r=13$

$8r=13$

$r=\frac{13}{8}$ ohm

Resistance of long piece of wire= $7\times\frac{13}{8}=\frac{91}{8}\Omega$

Resistance of short piece of wire = $\frac{13}{8}\Omega$

Resistivity of wire and cross section area of wire remains same .

Let L be the total length of wire and L' be the length of short piece of wire.

We know that

$R=\frac{\rho L}{A}$ = $\frac{\rho}{A}L=KL$

$\frac{R}{L}=K$

Where K= $\frac{\rho}{A}$ =Constant

Using the formula

$\frac{13}{L}=\frac{\frac{13}{8}}{L'}$

$\frac{L'}{L}=\frac{13}{8}\times \frac{1}{13}=\frac{1}{8}$

$L'=\frac{L}{8}$

Length of short piece of wire=L'= $\frac{L}{8}$

Length of long piece of wire= $L-L'=L-\frac{L}{8}=\frac{8L-L}{8}=\frac{7}{8}L$

% of length of short piece of wire= $\frac{\frac{L}{8}}{L}\times 100=12.5%$ %

The resistance of the short piece= $\frac{13}{8}\Omega$

The resistance of the long piece= $\frac{91}{8}\Omega$

8 0

4 years ago

two tugboats pull a disabled supertanker. each tug exerts a constant force of 2.20×106 n , one at an angle 19.0 ∘ west of north,

asambeis [7]

The amount of work the two tugboats completed on the supertanker W = 3.12 × 10^9 joules .

Work is a physics term used to describe the energy transfer that takes place when an object is moved over a distance by an external force, at least some . The component of the force acting along the path multiplied by the length of the path can be used to calculate work if the force is constant. Mathematically, this idea is expressed as W = fd, where W is the work and f is the force multiplied by d, the distance. Work is completed when the force is applied at an angle of with respect to the displacement. Performing work on a body involves moving it in its entirety from one location to another as well as other methods. However, the work is thought to be negative if the applied force is in opposition to the item's motion, indicating that energy is being pulled away from the object

Learn more about work here:

brainly.com/question/1374468

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7 0

1 year ago